The equilibrium constant, K, for 2 NO (g) + O2 (g) ⇌ 2 NO2 (g) is 6.9 x 102. What is the [NO] in an equilibrium mixture of gaseous NO, O2, and NO2 at 500 K that contains 1.5 x 10 –2 M O2 and 4.3 x 10 –3 M NO2?
A
4.15 x 10-4 M
B
1.34 x 10-3 M
C
2.04 x 10-2 M
D
1.80 x 10-6 M
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1
Identify the balanced chemical equation: 2 NO (g) + O2 (g) ⇌ 2 NO2 (g).
Write the expression for the equilibrium constant (K) for the reaction: K = ([NO2]^2) / ([NO]^2 * [O2]).
Substitute the given values into the equilibrium expression: K = 6.9 x 10^2, [O2] = 1.5 x 10^-2 M, and [NO2] = 4.3 x 10^-3 M.
Rearrange the equation to solve for [NO]^2: [NO]^2 = ([NO2]^2) / (K * [O2]).
Calculate [NO] by taking the square root of [NO]^2 to find the concentration of NO at equilibrium.