A sample of copper absorbs 3.53 kJ of heat, which increases the temperature by 25 ºC, determine the mass (in kg) of the copper sample if the specific heat capacity of copper is 0.385 J / g ºC.
A
0.73 kg
B
0.35 kg
C
0.37 kg
D
0.53 kg
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1
Identify the given values: heat absorbed (q) = 3.53 kJ, temperature change (ΔT) = 25 ºC, and specific heat capacity (c) = 0.385 J/g·ºC.
Convert the heat absorbed from kilojoules to joules: 1 kJ = 1000 J, so multiply 3.53 kJ by 1000 to get the value in joules.
Use the formula for heat transfer: q = m * c * ΔT, where q is the heat absorbed, m is the mass, c is the specific heat capacity, and ΔT is the temperature change.
Rearrange the formula to solve for mass (m): m = q / (c * ΔT).
Substitute the known values into the rearranged formula and solve for the mass in grams. Finally, convert the mass from grams to kilograms by dividing by 1000.