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Solutions and Concentration Calculations: Study Notes for Introductory Chemistry

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Solutions and Solution Concentration

Speeding Up the Dissolving Process

Several factors can influence the rate at which a solute dissolves in a solvent. Understanding these can help in laboratory and everyday settings.

  • Increasing Temperature: When the solution is warmed, particles move faster, increasing the rate of dissolution.

  • Stirring the Solution: Stirring spreads solute particles throughout the solvent, increasing contact and speeding up dissolution.

  • Crushing the Solute: Breaking solute into smaller pieces increases surface area exposed to the solvent, which increases the dissolving rate.

Example: Dissolving a sugar cube in water is faster if the water is warm, the cube is crushed, and the solution is stirred.

Calculating Solution Concentration (Percent by Mass)

The concentration of a solution can be expressed as percent by mass, which is the mass of solute divided by the total mass of the solution, multiplied by 100.

  • Formula:

  • Example Calculation: Dissolving 8.0 g NaCl in 100 g water:

Calculating Mass of Solute in a Given Solution

To find the mass of solute in a solution of known concentration and volume:

  • Step 1: Calculate total mass of solution.

  • Step 2: Use percent concentration to find mass of solute.

  • Example: In a 7.5% glucose solution, 25 g glucose is present in every 100 g solution. For 275 g solution: g glucose.

Molarity (M) and Solution Calculations

Molarity is a common unit of concentration, defined as moles of solute per liter of solution.

  • Formula:

  • Example: To prepare 0.625 M CuSO4 solution, calculate moles and mass needed for a given volume.

Steps for Preparing Solutions of Known Molarity

  1. Calculate moles of solute needed:

  2. Convert moles to grams using molar mass:

  3. Dissolve calculated mass in appropriate volume of solvent.

Example: To make 125 mL of 0.625 M CuSO4 solution:

  • Volume = 0.125 L

  • Moles needed = mol

  • Molar mass of CuSO4 = 63.5 + 32 + (16 × 4) = 159.5 g/mol

  • Mass needed = g

Dilution Calculations

When diluting a solution, the amount of solute remains constant, but the volume increases, lowering the concentration.

  • Formula: Where and are initial molarity and volume, and are final molarity and volume.

  • Example: To dilute 175 mL of 0.25 M HCl to 0.10 M, solve for final volume: mL

Sample Table: Solution Preparation and Dilution

Step

Calculation

Result

Moles of solute

e.g., mol

Mass of solute

Moles × Molar mass

e.g., g

Dilution volume

e.g., mL

Additional info:

  • These calculations are foundational for laboratory work, chemical manufacturing, and medical applications.

  • Always use proper units and significant figures in calculations.

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