객관식
Which of the following best describes the correct Lewis structure for (methyl formate)?
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1. A Review of General Chemistry
Lewis Structure
객관식
Which of the following best represents the correct Lewis structure for (selenium monoxide)?
A
is double-bonded to , with no lone pairs on either atom.
B
is triple-bonded to , with one lone pair on and one lone pair on .
C
is double-bonded to , with two lone pairs on and two lone pairs on .
D
is single-bonded to , with three lone pairs on and three lone pairs on .
검증된 단계별 안내1
Step 1: Determine the total number of valence electrons available for bonding in selenium monoxide (SeO). Selenium (Se) is in group 16 and has 6 valence electrons, and oxygen (O) is also in group 16 with 6 valence electrons. So, total valence electrons = 6 (Se) + 6 (O) = 12 electrons.
Step 2: Draw a skeletal structure connecting Se and O with a single bond initially. This single bond accounts for 2 electrons, so subtract these from the total valence electrons: 12 - 2 = 10 electrons remaining.
Step 3: Distribute the remaining electrons as lone pairs to satisfy the octet rule for each atom. Start by placing lone pairs on the more electronegative atom (oxygen) to complete its octet, then place remaining electrons on selenium.
Step 4: Check if both atoms have a complete octet (8 electrons around each). If not, form double or triple bonds by converting lone pairs into bonding pairs between Se and O until both atoms satisfy the octet rule.
Step 5: Confirm the final Lewis structure by counting all electrons around each atom and ensuring the total equals the original valence electron count (12). The correct structure will have Se double-bonded to O, with two lone pairs on each atom.
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