The compound below contains alternating double bonds and has 14 π electrons (4n + 2 with n = 3), therefore, it is aromatic. Is this statement true or false? Explain.

True. The compound has all the conditions for it to be aromatic.

True. The compound is aromatic because all the electrons are delocalized.

False. Only fully conjugated monocyclic hydrocarbons with less than nine carbons can be aromatic.

False. The compound is not aromatic because it is not planar, and the π-orbitals will not be lined up.