for-the-acid-base-reactions-below-prove-that-the-equilibrium-lies-in-the-directi

Question

For the acid-base reactions below, prove that the equilibrium lies in the direction indicated in the reactions by comparing the pK_{a} values of the acids on both sides of the equilibrium arrow.

Accepted Answer

a. The pK_{a} values of the acids on both sides of the reaction are similar, so each would have a similar amount at equilibrium.b. The pK_{a} value of the acid on the reactant side is greater, making it the weaker acid, so the reactant side is favored.

Answer

a. The pK_{a} values of the acids on both sides of the reaction are similar, so each would have a similar amount at equilibrium.b. The pK_{a} value of the acid on the reactant side is greater, making it the stronger acid, so the reactant side is favored.

Answer

a. The pK_{a} value of the acid on the reactant side is greater, making it the stronger acid, so the reactant side is favored.b. The pK_{a} value of the acid on the product side is greater, making it the stronger acid, so the product side is favored.

Answer

a. The pK_{a} value of the acid on the product side is lesser, making it the weaker acid, so the product side is favored.b. The pK_{a} value of the acid on the product side is lesser, making it the weaker acid, so the product side is favored.

For the acid-base reactions below, prove that the equilibrium lies in the direction indicated in the reactions by comparing the pKa values of the acids on both sides of the equilibrium arrow.

For the acid-base reactions below, prove that the equilibrium lies in the direction indicated in the reactions by comparing the pK_a values of the acids on both sides of the equilibrium arrow.