ce-direction-on-q2-is-rvector-012-ihat-016-jhat-m-what-is-the-force-vector-on-q2

Question

A charge q1=−5.0q1 = -5.0 microcoulombs exerts a force on q2=+2.0q2 = +2.0 microcoulombs. The displacement vector pointing in the actual force direction on q2q2 is R→=−0.12i^+0.16j^\overrightarrow{R}=-0.12\hat{i}+0.16\hat{j} m	ext{m}. What is the force vector on q2q2?

Accepted Answer

−1.35i^+1.80j^-1.35\hat{i}+1.80\hat{j} N	ext{N}

Answer

−6.74i^+8.99j^-6.74\hat{i}+8.99\hat{j} N	ext{N}

Answer

1.35i^−$$1.80j^1.35$$\hat{i}-1.80\hat{j} N	ext{N}

Answer

−0.27i^+0.36j^-0.27\hat{i}+0.36\hat{j} N	ext{N}

A charge q1=−5.0q1 = -5.0 microcoulombs exerts a force on q2=+2.0q2 = +2.0 microcoulombs. The displacement vector pointing in the actual force direction on q2q2 is R→=−0.12i^+0.16j^\(\overrightarrow{R}\)=-0.12\(\hat{i}\)+0.16\(\hat{j}\) m\(\text{m}\). What is the force vector on q2q2?

A charge $q 1 = - 5.0$ microcoulombs exerts a force on $q 2 equals positive 2.0$ microcoulombs. The displacement vector pointing in the actual force direction on $q 2$ is $\vec{R} = - 0.12 \hat{i} + 0.16 \hat{j}$ $m$ . What is the force vector on $q 2$ ?