Q: A projectile is launched from point O with an initial velocity $$v_0 at an $$angle above the horizontal, as shown in the diagram. If the height of the launch point above the ground is $$h$$, and the projectile lands at point P a horizontal distance $$D$$ away, which equation correctly gives the time $$t it $$takes for the projectile to reach point P?

$$t = \frac{v_0$ \sin \theta + \sqrt{(v_0$ \sin \$$theta)^2$$ + 2gh}}{g}$$

Q: In the scenario shown, what is the horizontal distance $$D ($$range) the projectile travels before hitting the ground, assuming the launch height is $$h$$ and the initial velocity is $$v_0 at $$angle $$\theta$$?

$$D = v_0$ \cos \theta \cdot \left( \frac{v_0$ \sin \theta + \sqrt{(v_0$ \sin \$$theta)^2$$ + 2gh}}{g} \right)$$

Question 1

A projectile is launched from point O with an initial velocity $$v_0 at an $$angle above the horizontal, as shown in the diagram. If the height of the launch point above the ground is $$h$$, and the projectile lands at point P a horizontal distance $$D$$ away, which equation correctly gives the time $$t it $$takes for the projectile to reach point P?

Accepted Answer

$$t = \frac{v_0$ \sin 	heta + \sqrt{(v_0$ \sin \$$theta)^2$$ + 2gh}}{g}$$

Question 2

In the scenario shown, what is the horizontal distance $$D ($$range) the projectile travels before hitting the ground, assuming the launch height is $$h$$ and the initial velocity is $$v_0 at $$angle $$	heta$$?

Accepted Answer

$$D = v_0$ \cos 	heta \cdot \left( \frac{v_0$ \sin 	heta + \sqrt{(v_0$ \sin \$$theta)^2$$ + 2gh}}{g} ight)$$

Question 3

If air resistance is neglected, which statement best describes the trajectory of the projectile launched from point O?

Accepted Answer

It follows a parabolic curve.

Question 4

Suppose the projectile in the diagram is launched horizontally from height $$h. At $$the same instant, a second object is simply dropped from the same height. Which object hits the ground first?

Accepted Answer

Both hit the ground at the same time.

Question 5

If the initial velocity $$v_0 is $$doubled, how does the horizontal range $$D$$ change for a projectile launched from height $$h at $$angle $$	heta$$?

Accepted Answer

The range $$D is $$quadrupled.

Question 6

Which component of the projectile’s acceleration is responsible for changing its speed during flight?

Accepted Answer

The component parallel to velocity.

Question 7

For the projectile shown, what is the vertical component of its velocity just before it hits the ground?

Accepted Answer

$$v_{y} = -\sqrt{(v_0$ \sin \$$theta)^2$$ + 2gh}$$

Question 8

If the projectile is launched at an angle $$	heta$$ such that $$\sin 2	heta = 1$$, what is the launch angle?

Accepted Answer

$$	heta = 45^\circ$$

Question 9

Which of the following best explains why the horizontal and vertical motions of the projectile are independent?

Accepted Answer

Because the time of flight is determined only by the vertical motion.

Question 10

If the projectile is launched from point O with $$v_0 at $$angle $$	heta$$, what is the initial vertical velocity component?

Accepted Answer

$$v_0$$ \sin 	heta$$

Kinematics in Two Dimensions: Motion, Projectile Motion, and Circular Motion

스터디 가이드 - 연습 문제

학습 가이드 - 플래시카드