뒤로Physics 2010 Exam 3 Practice Guidance: Momentum, Energy & Thermodynamics
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Q1. A system of two particles has zero total momentum. Which must be true?
Background
Topic: Conservation of Momentum
This question tests your understanding of how the momenta of individual particles combine to give the total momentum of a system.
Key Terms:
Momentum ():
Conservation of Momentum: The total momentum of a system remains constant if no external forces act.
Step-by-Step Guidance
Recall that momentum is a vector quantity, so direction matters as well as magnitude.
For the total momentum to be zero, the sum of the individual momenta must cancel out.
Consider what must be true about the velocities and masses of the particles for their momenta to add to zero.
Think about whether both particles must be at rest, or if they can be moving with equal and opposite momenta.
Try solving on your own before revealing the answer!
Final Answer: (C) The particles' momenta are equal in magnitude and opposite in direction
For the total momentum to be zero, the momenta must cancel each other out. This does not require both particles to be at rest, but their momenta must be equal and opposite.
Q2. A ball bounces off a wall with the same speed. The change in the ball's momentum:
Background
Topic: Impulse and Momentum Change
This question tests your understanding of how momentum changes when an object reverses direction after a collision.
Key Terms:
Momentum ():
Impulse ():
Step-by-Step Guidance
Consider the initial and final velocities of the ball before and after hitting the wall.
Since the speed is the same but the direction is reversed, the velocity changes sign.
Calculate the change in momentum: .
Think about how this relates to the impulse delivered by the wall.
Try solving on your own before revealing the answer!
Final Answer: (D) Equals the impulse delivered by the wall, directed away from the wall
The change in momentum is equal to the impulse delivered by the wall, and since the ball bounces back, the direction is away from the wall.
Q3. In a perfectly elastic head-on collision between equal masses, one initially at rest:
Background
Topic: Elastic Collisions
This question tests your understanding of how velocities are exchanged in elastic collisions between equal masses.
Key Terms:
Elastic Collision: Both momentum and kinetic energy are conserved.
Conservation of Momentum:
Conservation of Kinetic Energy:
Step-by-Step Guidance
Set up the conservation equations for momentum and kinetic energy.
Plug in the values: , (one at rest).
Solve for the final velocities and .
Interpret the physical meaning of the result: what happens to the moving and stationary objects?
Try solving on your own before revealing the answer!
Final Answer: (B) The moving object stops; the stationary one moves with the original speed
In a perfectly elastic collision between equal masses, the moving object transfers its velocity to the stationary one.
Q4. The work done by the normal force on a block sliding along a level surface is:
Background
Topic: Work and Forces
This question tests your understanding of how work is calculated for forces perpendicular to displacement.
Key Terms:
Work ():
Normal Force: Acts perpendicular to the surface.
Step-by-Step Guidance
Recall the definition of work and the angle between force and displacement.
For the normal force, the angle between force and displacement is .
Calculate and see how it affects the work done.
Consider whether the normal force does any work as the block moves horizontally.
Try solving on your own before revealing the answer!
Final Answer: (C) Zero, because the normal force is perpendicular to the displacement
Work is zero when the force is perpendicular to the displacement, since .
Q5. A spring stretched by distance x has PE = U. If stretched by 3x, the PE is:
Background
Topic: Elastic Potential Energy
This question tests your understanding of how potential energy in a spring depends on displacement.
Key Formula:
Elastic Potential Energy:
Step-by-Step Guidance
Write the expression for potential energy for displacement and for .
Compare for and for .
Calculate and relate it to .
Determine the factor by which the potential energy increases.
Try solving on your own before revealing the answer!
Final Answer: (C) 9U
Since potential energy depends on the square of displacement, stretching by increases PE by a factor of $9$.
Q6. A projectile (no air resistance) has minimum kinetic energy at:
Background
Topic: Projectile Motion and Energy
This question tests your understanding of how kinetic energy changes during projectile motion.
Key Terms:
Kinetic Energy ():
At the highest point, vertical velocity is zero.
Step-by-Step Guidance
Consider how the velocity components change as the projectile rises and falls.
At the highest point, the vertical component of velocity is zero, but the horizontal component remains.
Calculate kinetic energy at launch, at the highest point, and at impact.
Compare these values to determine where KE is minimum.
Try solving on your own before revealing the answer!
Final Answer: (B) At the highest point, where the vertical velocity component is zero
Kinetic energy is minimized at the highest point because only the horizontal velocity remains.
Q7. Two blocks collide elastically. Block 1 is heavier, Block 2 was at rest. After, Block 1:
Background
Topic: Elastic Collisions and Mass Ratio
This question tests your understanding of how mass affects the outcome of elastic collisions.
Key Terms:
Elastic Collision: Both momentum and kinetic energy are conserved.
Mass ratio:
Step-by-Step Guidance
Set up the conservation equations for momentum and kinetic energy.
Consider the case where and Block 2 is initially at rest.
Analyze the final velocity of Block 1 after the collision.
Determine whether Block 1 stops, bounces back, or continues forward.
Try solving on your own before revealing the answer!
Final Answer: (B) Continues in the same direction with reduced speed (if m1 > m2)
Block 1 slows down but continues forward if it is heavier than Block 2.
Q8. An ideal gas pressure is doubled at constant temperature. Volume:
Background
Topic: Ideal Gas Law
This question tests your understanding of the relationship between pressure and volume at constant temperature.
Key Formula:
Ideal Gas Law:
Step-by-Step Guidance
Write the ideal gas law and identify which variables are held constant.
At constant and , and are inversely related.
Express the relationship: .
Set and solve for in terms of .
Try solving on your own before revealing the answer!
Final Answer: (B) Is halved
Doubling the pressure at constant temperature halves the volume.
Q9. Which best explains why rms speed of gas molecules increases with temperature?
Background
Topic: Kinetic Theory of Gases
This question tests your understanding of how temperature relates to molecular speed.
Key Formula:
Root-mean-square speed:
Average kinetic energy:
Step-by-Step Guidance
Recall that temperature is a measure of average kinetic energy.
As temperature increases, kinetic energy and rms speed increase.
Examine the formula for and see how it depends on .
Identify which explanation matches this relationship.
Try solving on your own before revealing the answer!
Final Answer: (B) Temperature is a direct measure of average molecular kinetic energy
Higher temperature means higher average kinetic energy, which increases rms speed.
Q10. A block slides from rest down a frictionless ramp onto a rough surface. The work-energy theorem says:
Background
Topic: Work-Energy Theorem
This question tests your understanding of how net work relates to changes in kinetic energy.
Key Formula:
Work-Energy Theorem:
Step-by-Step Guidance
Recall the work-energy theorem and what it says about net work and kinetic energy.
Consider the effects of friction on the block's energy as it moves onto the rough surface.
Determine how the net work relates to the change in kinetic energy.
Compare the options to see which matches the theorem.
Try solving on your own before revealing the answer!
Final Answer: (B) Net work equals change in kinetic energy
The work-energy theorem states that the net work done on an object equals its change in kinetic energy.
Q11. Compared to N2 (M = 28 g/mol), O2 (M = 32 g/mol) molecules at the same temperature have:
Background
Topic: Molecular Speed and Kinetic Energy
This question tests your understanding of how molecular mass affects rms speed and kinetic energy at constant temperature.
Key Formula:
Step-by-Step Guidance
Compare the molar masses of N2 and O2.
Use the formula to see how mass affects speed.
Use the formula to see how temperature affects kinetic energy.
Determine which properties are the same and which differ.
Try solving on your own before revealing the answer!
Final Answer: (B) Lower rms speed but the same average KE
At the same temperature, heavier molecules have lower rms speed, but average kinetic energy depends only on temperature.
Q12. A heat pump moves heat from cold to warm reservoir. This process:
Background
Topic: Second Law of Thermodynamics
This question tests your understanding of how heat pumps operate and the role of external work.
Key Terms:
Second Law of Thermodynamics: Heat naturally flows from hot to cold, not the reverse without work.
Heat Pump: Moves heat from cold to warm by doing work.
Step-by-Step Guidance
Recall the second law and how it applies to heat transfer.
Consider whether external work is required to move heat from cold to warm.
Determine which options correctly describe the process.
Eliminate options that violate physical laws.
Try solving on your own before revealing the answer!
Final Answer: (B) Is possible only if external work is done on the system
Heat pumps require external work to move heat from cold to warm, consistent with the second law.
Q13. A 1 kg object at 2 m/s has momentum p1. A 2 kg object at 1 m/s has momentum p2. Which is correct?
Background
Topic: Comparing Momentum
This question tests your ability to calculate and compare momentum for different masses and velocities.
Key Formula:
Momentum:
Step-by-Step Guidance
Calculate and .
Compare the values to see which is greater.
Consider whether direction matters in this comparison.
Determine if the momenta are equal, or if one is larger.
Try solving on your own before revealing the answer!
Final Answer: (C) p1 = p2
Both objects have momentum kg·m/s, so their momenta are equal.
Q14. When catching a fast ball, moving your hands backward as you catch it:
Background
Topic: Impulse and Force
This question tests your understanding of how increasing stopping time affects force during a collision.
Key Formula:
Impulse:
Average force:
Step-by-Step Guidance
Recall that impulse is the change in momentum.
Increasing the time over which the ball is stopped reduces the average force.
Consider how moving your hands backward affects stopping time and force.
Identify which option matches this reasoning.
Try solving on your own before revealing the answer!
Final Answer: (B) Increases stopping time, reducing average force on your hands
By increasing stopping time, the average force is reduced, making it easier to catch the ball.
Q15. An ideal gas molecule in a cubic box: if temperature doubles at constant volume, the average force on the wall by each molecule:
Background
Topic: Kinetic Theory and Pressure
This question tests your understanding of how temperature affects the force exerted by gas molecules.
Key Formula:
Pressure:
Ideal Gas Law:
Force is proportional to pressure, which is proportional to temperature at constant volume.
Step-by-Step Guidance
Recall that at constant volume, pressure is proportional to temperature.
Doubling temperature doubles pressure.
Since force is related to pressure, consider how force changes when temperature doubles.
Determine the relationship between force and temperature.
Try solving on your own before revealing the answer!
Final Answer: (B) Doubles
Doubling the temperature at constant volume doubles the average force exerted by each molecule.