뒤로Physics 2010 Exam 3 Practice: Step-by-Step Guidance
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Q1. A system of two particles has zero total momentum. Which must be true?
Background
Topic: Conservation of Momentum
This question tests your understanding of what it means for a system to have zero total momentum and how the momenta of individual particles relate to the total.
Key Terms:
Momentum (): The product of mass and velocity, .
System: The collection of particles being considered.
Step-by-Step Guidance
Recall that the total momentum of a system is the vector sum of the momenta of all particles: .
If , then (equal in magnitude, opposite in direction).
Consider whether both particles must be at rest, or if they can be moving with equal and opposite momenta.
Think about whether equal masses are required, or if only the momenta need to be equal and opposite.
Try solving on your own before revealing the answer!
Final Answer: (C) The particles' momenta are equal in magnitude and opposite in direction
Zero total momentum means the vector sum of the two momenta is zero, so they must be equal in magnitude and opposite in direction. The particles do not have to be at rest or have equal masses.
Q2. A ball bounces off a wall with the same speed. The change in the ball's momentum:
Background
Topic: Impulse and Momentum Change
This question tests your understanding of how momentum changes when an object reverses direction after a collision.
Key Terms and Formulas:
Momentum:
Impulse:
Step-by-Step Guidance
Let the ball's initial velocity toward the wall be ; after bouncing, its velocity is (opposite direction, same speed).
Calculate the change in momentum: .
Simplify the expression to see how the change relates to the original momentum.
Recall that impulse delivered by the wall equals the change in momentum.
Try solving on your own before revealing the answer!
Final Answer: (B) Is twice the original momentum, directed away from the wall
The change in momentum is , which is twice the original magnitude but in the opposite direction. The impulse delivered by the wall is also in this direction.
Q3. In a perfectly elastic head-on collision between equal masses, one initially at rest:
Background
Topic: Elastic Collisions
This question tests your understanding of the outcomes of elastic collisions between equal masses, especially when one is initially at rest.
Key Concepts:
Elastic Collision: Both momentum and kinetic energy are conserved.
Equal Masses:
Step-by-Step Guidance
Write conservation of momentum: , with .
Write conservation of kinetic energy: .
Solve the equations for and .
Interpret the physical meaning: what happens to each mass after the collision?
Try solving on your own before revealing the answer!
Final Answer: (B) The moving object stops; the stationary one moves with the original speed
In a perfectly elastic collision between equal masses, the moving mass comes to rest and the stationary mass moves off with the original speed of the first.
Q4. The work done by the normal force on a block sliding along a level surface is:
Background
Topic: Work and Forces
This question tests your understanding of when a force does work, specifically the normal force on a horizontal surface.
Key Concepts:
Work:
Normal Force: Acts perpendicular to the surface.
Step-by-Step Guidance
Recall that work is the dot product of force and displacement vectors.
On a level surface, the normal force is vertical, while displacement is horizontal.
Calculate the angle between the normal force and displacement.
Determine if the normal force does any work based on the angle.
Try solving on your own before revealing the answer!
Final Answer: (C) Zero, because the normal force is perpendicular to the displacement
Work is zero when the force is perpendicular to the displacement, as .
Q5. A spring stretched by distance x has PE = U. If stretched by 3x, the PE is:
Background
Topic: Elastic Potential Energy
This question tests your understanding of how the potential energy stored in a spring depends on the amount it is stretched.
Key Formula:
Step-by-Step Guidance
Write the expression for potential energy at stretch : .
Substitute for to find the new potential energy: .
Simplify the expression to see how relates to .
Compare the new energy to the original energy .
Try solving on your own before revealing the answer!
Final Answer: (C) 9U
Potential energy increases with the square of the stretch, so stretching by gives .
Q6. A projectile (no air resistance) has minimum kinetic energy at:
Background
Topic: Projectile Motion and Energy
This question tests your understanding of how kinetic energy changes during projectile motion.
Key Concepts:
Kinetic Energy:
At the highest point, vertical velocity is zero.
Step-by-Step Guidance
Recall that as a projectile rises, its speed decreases due to gravity.
At the highest point, the vertical component of velocity is zero, but the horizontal component remains.
Calculate kinetic energy at launch, at the highest point, and at impact.
Compare these values to determine where kinetic energy is minimized.
Try solving on your own before revealing the answer!
Final Answer: (B) At the highest point, where the vertical velocity component is zero
Kinetic energy is minimized at the top because only the horizontal component of velocity remains.
Q7. Two blocks collide elastically. Block 1 is heavier, Block 2 was at rest. After, Block 1:
Background
Topic: Elastic Collisions, Conservation of Momentum
This question tests your understanding of the outcome of elastic collisions when one mass is greater than the other and one block is initially at rest.
Key Concepts:
Momentum and kinetic energy are conserved in elastic collisions.
Relative masses affect the final velocities.
Step-by-Step Guidance
Write the equations for conservation of momentum and kinetic energy for two masses, , with .
Solve for the final velocity of Block 1, , in terms of and .
Analyze the result for to see if Block 1 stops, bounces back, or continues forward.
Consider the special case when .
Try solving on your own before revealing the answer!
Final Answer: (B) Continues in the same direction with reduced speed (if m1 > m2)
After the collision, Block 1 keeps moving forward but with a lower speed if it is heavier than Block 2.
Q8. An ideal gas pressure is doubled at constant temperature. Volume:
Background
Topic: Ideal Gas Law
This question tests your understanding of the relationship between pressure and volume at constant temperature (Boyle's Law).
Key Formula:
Step-by-Step Guidance
At constant temperature and number of moles, .
If pressure doubles (), substitute into the equation to solve for .
Compare to to see how volume changes.
Try solving on your own before revealing the answer!
Final Answer: (B) Is halved
Doubling the pressure at constant temperature causes the volume to decrease by half (Boyle's Law).
Q9. Which best explains why rms speed of gas molecules increases with temperature?
Background
Topic: Kinetic Theory of Gases
This question tests your understanding of the relationship between temperature and molecular motion in gases.
Key Formula:
Temperature is proportional to average kinetic energy.
Step-by-Step Guidance
Recall that temperature is a measure of the average kinetic energy of molecules.
As temperature increases, average kinetic energy increases, leading to higher rms speed.
Review the formula for rms speed and see how it depends on temperature.
Try solving on your own before revealing the answer!
Final Answer: (B) Temperature is a direct measure of average molecular kinetic energy
As temperature increases, so does the average kinetic energy and thus the rms speed of molecules.
Q10. A block slides from rest down a frictionless ramp onto a rough surface. The work-energy theorem says:
Background
Topic: Work-Energy Theorem
This question tests your understanding of the work-energy theorem and how it applies to a block moving from a frictionless to a rough surface.
Key Formula:
Step-by-Step Guidance
Recall the work-energy theorem: net work done on an object equals its change in kinetic energy.
Consider the work done by friction on the rough surface and how it affects the block's kinetic energy.
Relate the net work to the change in kinetic energy as the block moves from the ramp to the rough surface.
Try solving on your own before revealing the answer!
Final Answer: (B) Net work equals change in kinetic energy
The work-energy theorem states that the net work done on an object is equal to its change in kinetic energy.
Q11. Compared to N2 (M = 28 g/mol), O2 (M = 32 g/mol) molecules at the same temperature have:
Background
Topic: Kinetic Theory of Gases
This question tests your understanding of how molecular mass affects rms speed and average kinetic energy at a given temperature.
Key Formula:
Average kinetic energy per molecule: (independent of mass)
Step-by-Step Guidance
Compare the molar masses of N2 and O2.
Use the rms speed formula to see how increasing molar mass affects speed at constant temperature.
Recall that average kinetic energy depends only on temperature, not mass.
Try solving on your own before revealing the answer!
Final Answer: (B) Lower rms speed but the same average KE
O2 molecules have a higher mass, so lower rms speed, but average kinetic energy is the same at a given temperature.
Q12. A heat pump moves heat from cold to warm reservoir. This process:
Background
Topic: Second Law of Thermodynamics
This question tests your understanding of how heat pumps work and the requirements for moving heat against a temperature gradient.
Key Concepts:
Heat naturally flows from hot to cold unless work is done.
Second Law of Thermodynamics: Heat cannot spontaneously flow from cold to hot without external work.
Step-by-Step Guidance
Recall the direction of natural heat flow and what is required to reverse it.
Consider whether a heat pump can operate without external work.
Determine which statement best matches the second law of thermodynamics.
Try solving on your own before revealing the answer!
Final Answer: (B) Is possible only if external work is done on the system
A heat pump requires external work to move heat from cold to warm, in accordance with the second law.
Q13. A 1 kg object at 2 m/s has momentum p1. A 2 kg object at 1 m/s has momentum p2. Which is correct?
Background
Topic: Linear Momentum
This question tests your ability to calculate and compare the momenta of two objects with different masses and velocities.
Key Formula:
Step-by-Step Guidance
Calculate .
Calculate .
Compare the two values to determine which is greater, or if they are equal.
Consider if direction is relevant based on the information given.
Try solving on your own before revealing the answer!
Final Answer: (C) p1 = p2
Both objects have momentum of 2 kg·m/s, so their momenta are equal in magnitude.
Q14. When catching a fast ball, moving your hands backward as you catch it:
Background
Topic: Impulse and Force
This question tests your understanding of how increasing the time over which a force acts affects the average force experienced.
Key Formula:
Step-by-Step Guidance
Recall that impulse equals change in momentum, and can also be written as average force times time.
If you increase the time () over which the ball is stopped, what happens to the average force?
Consider the effect on your hands if you "give" with the ball versus stopping it abruptly.
Try solving on your own before revealing the answer!
Final Answer: (B) Increases stopping time, reducing average force on your hands
By increasing the time, the average force is reduced for the same change in momentum.
Q15. An ideal gas molecule in a cubic box: if temperature doubles at constant volume, the average force on the wall by each molecule:
Background
Topic: Kinetic Theory of Gases
This question tests your understanding of how temperature affects the pressure (and thus force) exerted by gas molecules at constant volume.
Key Formula:
Step-by-Step Guidance
At constant volume, pressure is directly proportional to temperature ().
If temperature doubles, pressure doubles, so the average force on the wall also doubles.
Relate this to the molecular collisions with the wall.
Try solving on your own before revealing the answer!
Final Answer: (B) Doubles
Doubling the temperature at constant volume doubles the average force exerted by each molecule on the wall.