뒤로Physics Exam Practice: Momentum, Energy, Thermodynamics, and Gas Laws
스터디 가이드 - 스마트 노트
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Q16. Two players collide: A 70.0 kg running back (north, 5.00 m/s) and an 80.0 kg linebacker (west, 4.00 m/s) grab on. (a) Find x and y components of total momentum before collision. (b) Find the velocity (magnitude and direction) of the pair just after. (c) How much KE is lost?
Background
Topic: Conservation of Momentum & Kinetic Energy in Collisions
This question tests your understanding of vector momentum, conservation of momentum in two dimensions, and energy loss in inelastic collisions.
Key Terms and Formulas:
Momentum:
Conservation of Momentum:
Kinetic Energy:
Step-by-Step Guidance
Assign coordinate axes: Let north be the direction and west be the direction.
Calculate the momentum components for each player:
Running back: ,
Linebacker: ,
Add the momentum components to find total and before collision.
After collision, the players stick together. Use conservation of momentum to find the combined velocity vector:
To find the magnitude and direction, use:
Magnitude:
Direction:
For kinetic energy lost, compare total KE before and after collision:
Calculate for each player and sum.
Calculate for the combined mass and velocity.
KE lost =
Try solving on your own before revealing the answer!
Final Answer:
(a) kg·m/s, kg·m/s
(b) m/s, (measured from axis, or northwest)
(c) J
The collision is inelastic, so kinetic energy is not conserved, but momentum is.
Q17. A 4.00 kg bomb at rest explodes into three pieces. Piece 1 (1.00 kg) flies north at 20.0 m/s. Piece 2 (1.50 kg) flies east at 16.0 m/s. (a) Find the mass of Piece 3. (b) Find Piece 3's velocity (magnitude and direction). (c) Find total KE released.
Background
Topic: Conservation of Momentum & Energy in Explosions
This question tests your ability to apply conservation of momentum in two dimensions and calculate kinetic energy released.
Key Terms and Formulas:
Conservation of Momentum:
Kinetic Energy:
Step-by-Step Guidance
Find the mass of Piece 3:
Set up momentum conservation in both and directions. The bomb starts at rest, so total momentum after must be zero.
Calculate and for Pieces 1 and 2, then solve for Piece 3's and (they must cancel the others).
Find Piece 3's velocity components: ,
Calculate magnitude and direction: ,
Find total KE released: sum for all three pieces.
Try solving on your own before revealing the answer!
Final Answer:
(a) kg
(b) m/s, direction: southwest ( from east)
(c) J
Momentum is conserved, and the energy comes from the explosion.
Q18. Potential energy function: (J, in m). (a) Find all equilibrium positions (). (b) Determine which are stable (local minimum) and which are unstable. (c) Describe the motion of a 0.500 kg object released from rest at . (d) Find its speed at m.
Background
Topic: Potential Energy, Equilibrium, and Motion in a Potential
This question tests your understanding of equilibrium points, stability, and energy conservation.
Key Terms and Formulas:
Equilibrium:
Stability: (second derivative test)
Conservation of Energy:
Kinetic Energy:
Step-by-Step Guidance
Find equilibrium positions by setting and solving for .
Use the second derivative to determine stability at each equilibrium.
For , describe the motion based on the potential shape and force direction.
Use energy conservation to find speed at m:
Set up the equation for at m, but stop before plugging in numbers.
Try solving on your own before revealing the answer!
Final Answer:
(a) Equilibrium at , m
(b) m are stable (minima), is unstable (maximum)
(c) The object moves away from toward m
(d) m/s at m
Energy conservation allows calculation of speed at any position.
Q19. A 0.300 kg block is dropped from 0.800 m onto a spring ( N/m) on the floor. (a) Find maximum spring compression. (b) Find maximum elastic PE stored. (c) At maximum compression, what is the net upward force on the block? (d) After bouncing, how high above the drop point does the block rise?
Background
Topic: Energy Conservation, Springs, and Forces
This question tests your understanding of gravitational potential energy, elastic potential energy, and forces at equilibrium.
Key Terms and Formulas:
Gravitational PE:
Elastic PE:
Force from spring:
Net force:
Step-by-Step Guidance
Set up energy conservation: to solve for maximum compression .
Calculate maximum elastic PE using .
At maximum compression, find and subtract to get net upward force.
After bouncing, use energy conservation to find the height above the drop point.
Set up the equations for each part, but stop before final calculations.
Try solving on your own before revealing the answer!
Final Answer:
(a) m
(b) J
(c) N upward
(d) The block rises m above the drop point
Energy is conserved, and the spring launches the block back up.
Q20. An 8.00 g bullet at 350 m/s embeds in a 2.00 kg block on a 1.50 m-high table. (a) Find the block+bullet speed just after impact. (b) How far from the table base does the block land? (c) How much KE was lost in the collision?
Background
Topic: Conservation of Momentum, Projectile Motion, and Energy Loss
This question tests your ability to apply conservation of momentum, analyze projectile motion, and calculate energy loss in inelastic collisions.
Key Terms and Formulas:
Momentum:
Conservation of Momentum:
Projectile motion:
Kinetic Energy:
Step-by-Step Guidance
Convert bullet mass to kg: kg
Use conservation of momentum to find combined speed just after impact.
Calculate time to fall from 1.50 m using .
Find horizontal distance:
Calculate KE before and after collision to find KE lost.
Try solving on your own before revealing the answer!
Final Answer:
(a) m/s
(b) m
(c) J
Momentum is conserved, but kinetic energy is not in this inelastic collision.
Q21. An 850 kg roller coaster car starts from rest at h = 30.0 m on a frictionless track with a loop (R = 7.50 m, bottom at ground) and then a second hill. (a) Find speed at the top of the loop. (b) Find normal force at top of loop. (c) Find maximum height h2 the car can reach after the loop.
Background
Topic: Conservation of Energy, Circular Motion, and Forces
This question tests your understanding of energy conservation, centripetal force, and normal force in circular motion.
Key Terms and Formulas:
Energy Conservation:
Centripetal Force:
Normal Force at top:
Step-by-Step Guidance
Use energy conservation to find speed at the top of the loop: initial PE minus PE at top equals KE at top.
Calculate centripetal force required at the top of the loop.
Find normal force:
For maximum height after the loop, use energy conservation (subtract KE at top from total energy).
Set up equations for each part, but stop before final calculations.
Try solving on your own before revealing the answer!
Final Answer:
(a) m/s at top of loop
(b) N
(c) m
Energy is conserved, and normal force is reduced at the top due to centripetal acceleration.
Q22. An engine (P = 3.00 kW) propels a 1500 kg car. Road resistance is constant at f = 600 N. (a) Find the car's maximum (terminal) speed. (b) At instantaneous speed 4.00 m/s, find the car's acceleration. (c) How much work does the engine do in 30.0 s while moving at 4.00 m/s?
Background
Topic: Power, Forces, and Work
This question tests your understanding of power, force, acceleration, and work in the context of a moving vehicle.
Key Terms and Formulas:
Power:
Terminal speed:
Net force:
Acceleration:
Work:
Step-by-Step Guidance
Calculate terminal speed using
At m/s, find engine force:
Find net force:
Calculate acceleration:
Find work done in 30.0 s:
Try solving on your own before revealing the answer!
Final Answer:
(a) m/s
(b) m/s2
(c) J
Power limits the maximum speed, and work is the product of power and time.
Q23. Two flasks connected by a valve: Flask 1 (V1 = 2.00 L, 300 K, 3.00 atm); Flask 2 (V2 = 3.00 L, 300 K, 1.00 atm). Valve opens, gases mix at 300 K. (a) Find total moles before mixing. (b) Find final pressure. (c) Find rms speed of N2 at 300 K. (M = 0.0280 kg/mol, R = 8.314 J/mol K.)
Background
Topic: Ideal Gas Law and Kinetic Theory
This question tests your ability to use the ideal gas law and calculate molecular speeds.
Key Terms and Formulas:
Ideal Gas Law:
RMS speed:
Step-by-Step Guidance
Calculate moles in each flask using
Add moles for total before mixing.
After mixing, total volume is , total moles is sum, temperature is constant.
Use to find final pressure.
Calculate for N2 at 300 K.
Try solving on your own before revealing the answer!
Final Answer:
(a) mol
(b) atm
(c) m/s
Ideal gas law and kinetic theory allow calculation of pressure and molecular speed.
Q24. A piston compresses 0.500 mol of ideal gas from V1 = 10.0 L to V2 = 2.50 L at constant T = 350 K. (a) Find initial and final pressures. (b) The gas is then heated at constant volume until pressure triples. Find final temperature. (c) Find total work done on the gas in both processes.
Background
Topic: Ideal Gas Law, Thermodynamics, and Work
This question tests your understanding of gas laws, isothermal and isochoric processes, and work calculations.
Key Terms and Formulas:
Ideal Gas Law:
Isothermal work:
Isochoric process:
Step-by-Step Guidance
Use to find and for initial and final volumes.
For constant volume heating, pressure triples:
Calculate work done during isothermal compression using
Work done during isochoric heating is zero.
Set up total work calculation, but stop before final computation.
Try solving on your own before revealing the answer!
Final Answer:
(a) atm, atm
(b) K
(c) J
Work is done on the gas during compression, and temperature increases during heating.
Q25. A 0.500 kg copper block (c = 390 J/kg K) at 200 C is dropped into 2.00 kg of water at 20.0 C (c_water = 4186 J/kg K) in an insulated container. (a) Find the final equilibrium temperature. (b) How much heat did the copper lose? (c) How much heat did the water gain? (d) Verify heat lost equals heat gained.
Background
Topic: Calorimetry and Heat Transfer
This question tests your understanding of heat exchange, specific heat, and energy conservation.
Key Terms and Formulas:
Heat transfer:
Energy conservation:
Step-by-Step Guidance
Set up energy balance:
Solve for (final equilibrium temperature).
Calculate heat lost by copper:
Calculate heat gained by water:
Check that
Try solving on your own before revealing the answer!
Final Answer:
(a) C
(b) J
(c) J
(d) Heat lost equals heat gained, as expected for an isolated system.
Q26. How much heat converts 0.200 kg of ice at -20.0 C to steam at 130 C? (c_ice = 2090 J/kg K, c_water = 4186 J/kg K, c_steam = 2010 J/kg K; Lf = 3.34 x 10^5 J/kg, Lv = 2.26 x 10^6 J/kg.) Find the heat for each of five stages: (a) warm ice from -20 to 0 C, (b) melt ice, (c) warm water from 0 to 100 C, (d) boil water, (e) warm steam from 100 to 130 C, and (f) find the total.
Background
Topic: Phase Changes and Heat Calculations
This question tests your understanding of heat required for temperature changes and phase transitions.
Key Terms and Formulas:
Heat for temperature change:
Heat for melting:
Heat for boiling:
Step-by-Step Guidance
Calculate heat to warm ice:
Calculate heat to melt ice:
Calculate heat to warm water:
Calculate heat to boil water:
Calculate heat to warm steam:
Add all heats for total:
Try solving on your own before revealing the answer!
Final Answer:
(a) J
(b) J
(c) J
(d) J
(e) J
(f) J
Each stage requires a different calculation; sum for total heat.
Q27. A monatomic ideal gas (Cv = 3R/2 per mole) undergoes a cycle: (1) isochoric heating from T1 = 300 K, p1 = 1.00 x 10^5 Pa, V = 0.0200 m^3 to p2 = 3.00 x 10^5 Pa; (2) isobaric expansion back to T1; (3) isothermal compression back to the original state. (a) Find T after step 1. (b) Find V after step 2. (c) Find work done by gas in each step. (d) Find net work per cycle.
Background
Topic: Thermodynamic Cycles and Work
This question tests your understanding of thermodynamic processes, gas laws, and work calculations.
Key Terms and Formulas:
Isochoric:
Isobaric:
Isothermal work:
Work for isochoric:
Work for isobaric:
Step-by-Step Guidance
For step 1 (isochoric), use to find .
For step 2 (isobaric), use to find .
Calculate work for each step: isochoric (), isobaric (), isothermal ().
Set up net work per cycle as sum of works for all steps.
Stop before plugging in numbers for final net work.
Try solving on your own before revealing the answer!
Final Answer:
(a) K
(b) m3
(c) J, J, J
(d) Net work per cycle: $0$ J
The cycle returns to the original state, so net work is zero.