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Ch 05: Applying Newton's Laws
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610당신이 사용하는 게 아니라요?교과서 변경
5장, 문제 46

A small car with mass 0.8000.800 kg travels at constant speed on the inside of a track that is a vertical circle with radius 5.005.00 m (Fig. E5.455.45). If the normal force exerted by the track on the car when it is at the top of the track (point BB) is 6.006.00 N, what is the normal force on the car when it is at the bottom of the track (point AA)?
A diagram showing a small car on a vertical circular track, with points A and B labeled, and a radius of 5.00 m indicated.

검증된 단계별 안내
1
Step 1: Identify the forces acting on the car at the top of the track (point B). These include the gravitational force (mg) acting downward and the normal force (N_top) exerted by the track, also acting downward. The net force at the top is the centripetal force required to keep the car moving in a circular path.
Step 2: Write the equation for the net force at the top of the track using Newton's second law. The centripetal force is provided by the sum of the gravitational force and the normal force: Fnet=Ntop+mg. The centripetal force is also expressed as mv2/r, where v is the speed of the car and r is the radius of the circular track.
Step 3: Solve for the speed of the car (v) using the forces at the top of the track. Rearrange the equation: v2=r(Ntop+mg)/m. Substitute the given values for mass (m = 0.800 kg), radius (r = 5.00 m), normal force at the top (N_top = 6.00 N), and gravitational acceleration (g = 9.80 m/s²).
Step 4: At the bottom of the track (point A), the forces acting on the car are the gravitational force (mg) acting downward and the normal force (N_bottom) exerted by the track acting upward. The net force at the bottom is again the centripetal force required to keep the car moving in a circular path. Write the equation for the net force at the bottom: Nbottom-mg=mv2/r.
Step 5: Solve for the normal force at the bottom (N_bottom) by rearranging the equation: Nbottom=mv2/r+mg. Substitute the values for mass, radius, gravitational acceleration, and the speed of the car (v) calculated in Step 3 to find the normal force at the bottom.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
2m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Centripetal Force

Centripetal force is the net force acting on an object moving in a circular path, directed towards the center of the circle. For an object in vertical circular motion, this force is crucial for maintaining the circular trajectory. At the top of the circle, the gravitational force and the normal force both contribute to the centripetal force, while at the bottom, the normal force must overcome gravity to provide the necessary centripetal force.
추천 영상:
가이드 코스
06:48
Intro to Centripetal Forces

Normal Force

The normal force is the force exerted by a surface to support the weight of an object resting on it, acting perpendicular to the surface. In the context of circular motion, the normal force varies depending on the position of the object in the circle. At the top of the track, the normal force is reduced due to the gravitational force acting in the same direction, while at the bottom, it must counteract gravity and provide additional force for centripetal acceleration.
추천 영상:
가이드 코스
08:17
The Normal Force

Newton's Second Law

Newton's Second Law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass, expressed as F = ma. This principle is essential for analyzing forces in circular motion, as it allows us to calculate the net force required for the car to maintain its circular path. By applying this law at different points in the circular motion, we can determine the normal force at the bottom of the track.
추천 영상:
가이드 코스
06:54
Intro to Forces & Newton's Second Law
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