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Ch 29: Electromagnetic Induction
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610당신이 사용하는 게 아니라요?교과서 변경
29장, 문제 42b

A parallel-plate, air-filled capacitor is being charged as in Fig. 29.23. The circular plates have radius 4.00 cm, and at a particular instant the conduction current in the wires is 0.520 A. What is the rate at which the electric field between the plates is changing?

검증된 단계별 안내
1
First, understand that the conduction current in the wires is related to the displacement current between the plates of the capacitor. The displacement current is responsible for the changing electric field between the plates.
Recall the relationship between the displacement current \( I_d \) and the rate of change of the electric field \( \frac{dE}{dt} \) in a parallel-plate capacitor: \( I_d = \varepsilon_0 A \frac{dE}{dt} \), where \( \varepsilon_0 \) is the permittivity of free space and \( A \) is the area of the plates.
Calculate the area \( A \) of the circular plates using the formula \( A = \pi r^2 \), where \( r \) is the radius of the plates. Given \( r = 4.00 \) cm, convert this to meters for consistency in units.
Since the conduction current \( I_c \) is equal to the displacement current \( I_d \) in this scenario, set \( I_c = I_d \) and use the formula \( I_d = \varepsilon_0 A \frac{dE}{dt} \) to solve for \( \frac{dE}{dt} \). Rearrange the formula to \( \frac{dE}{dt} = \frac{I_c}{\varepsilon_0 A} \).
Substitute the known values into the equation: \( I_c = 0.520 \) A, \( \varepsilon_0 = 8.85 \times 10^{-12} \) C²/(N·m²), and the calculated area \( A \). This will give you the rate at which the electric field is changing between the plates.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Capacitor Basics

A capacitor is a device that stores electrical energy in an electric field, typically consisting of two conductive plates separated by an insulating material. The capacitance, which is the ability to store charge, depends on the area of the plates and the distance between them. Understanding how capacitors work is crucial for analyzing the electric field changes as they charge or discharge.
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가이드 코스
04:32
Phasors for Capacitors

Conduction Current

Conduction current refers to the flow of electric charge through a conductor, such as a wire, due to the movement of electrons. In the context of a charging capacitor, the conduction current is the rate at which charge is being transferred to the capacitor plates, influencing the electric field between them. It is measured in amperes (A) and is essential for determining the rate of change of the electric field.
추천 영상:

Changing Electric Field

The electric field between the plates of a capacitor changes as the capacitor charges or discharges. This change is related to the rate at which charge accumulates on the plates, which is directly linked to the conduction current. The rate of change of the electric field can be calculated using the relationship between current, charge, and electric field, providing insight into the dynamics of the capacitor's operation.
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가이드 코스
03:16
Intro to Electric Fields
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교과서 질문

A parallel-plate, air-filled capacitor is being charged as in Fig. 29.23. The circular plates have radius 4.00 cm, and at a particular instant the conduction current in the wires is 0.520 A. (a) What is the displacement current density jD in the air space between the plates?

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교과서 질문

A parallel-plate, air-filled capacitor is being charged as in Fig. 29.23. The circular plates have radius 4.00 cm, and at a particular instant the conduction current in the wires is 0.520 A. (c) What is the induced magnetic field between the plates at a distance of 2.00 cm from the axis? (d) At 1.00 cm from the axis?

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교과서 질문

The magnetic field B at all points within the colored circle shown in Fig. E29.15 has an initial magnitude of 0.750 T. (The circle could represent approximately the space inside a long, thin solenoid.) The magnetic field is directed into the plane of the diagram and is decreasing at the rate of -0.0350 T/s. If the ring is cut at some point and the ends are separated slightly, what will be the emf between the ends?

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