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Ch. 5 - Discrete Probability Distributions
Triola - Elementary Statistics 14th Edition
Triola14th EditionElementary StatisticsISBN: 9780137366446당신이 사용하는 게 아니라요?교과서 변경
5장, 문제 5.2.32a

In Exercises 31 and 32, assume that hybridization experiments are conducted with peas having the property that for offspring, there is a 0.75 probability that a pea has green pods (as in one of Mendel’s famous experiments).


Hybrids Assume that offspring peas are randomly selected in groups of 16.


a. Find the mean and standard deviation for the numbers of peas with green pods in the groups of 16.

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Step 1: Recognize that this is a binomial distribution problem because there are two possible outcomes for each pea: having green pods (success) or not having green pods (failure). The probability of success (green pods) is given as p = 0.75, and the number of trials (n) is 16.
Step 2: Recall the formula for the mean (μ) of a binomial distribution: μ = n × p. Substitute the given values of n = 16 and p = 0.75 into this formula to calculate the mean.
Step 3: Recall the formula for the standard deviation (σ) of a binomial distribution: σ = √(n × p × (1 - p)). Substitute the given values of n = 16, p = 0.75, and (1 - p) = 0.25 into this formula to calculate the standard deviation.
Step 4: Simplify the expressions for both the mean and the standard deviation. For the mean, multiply n and p. For the standard deviation, calculate the product n × p × (1 - p) and then take the square root of the result.
Step 5: Interpret the results. The mean represents the expected number of peas with green pods in a group of 16, and the standard deviation measures the variability in the number of peas with green pods across different groups of 16.

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주요 개념

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Binomial Distribution

The binomial distribution models the number of successes in a fixed number of independent Bernoulli trials, each with the same probability of success. In this case, the success is defined as a pea having green pods, with a probability of 0.75. The distribution is characterized by two parameters: the number of trials (n) and the probability of success (p).
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Mean & Standard Deviation of Binomial Distribution

Mean of a Binomial Distribution

The mean of a binomial distribution can be calculated using the formula μ = n * p, where n is the number of trials and p is the probability of success. For this problem, with 16 peas and a probability of 0.75 for green pods, the mean number of peas with green pods can be determined by substituting these values into the formula.
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가이드 코스
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Mean & Standard Deviation of Binomial Distribution

Standard Deviation of a Binomial Distribution

The standard deviation of a binomial distribution is calculated using the formula σ = √(n * p * (1 - p)). This formula accounts for the variability in the number of successes across the trials. In this scenario, it helps quantify how much the number of peas with green pods is expected to deviate from the mean in groups of 16.
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Mean & Standard Deviation of Binomial Distribution
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One of Mendel’s famous experiments with peas resulted in 580 offspring, and 152 of them were yellow peas. Mendel claimed that under the same conditions, 25% of offspring peas would be yellow. Assume that Mendel’s claim of 25% is true, and assume that a sample consists of 580 offspring peas.


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