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Ch. 1 - Trigonometric Functions
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161당신이 사용하는 게 아니라요?교과서 변경
2장, 문제 57

Determine whether each statement is possible or impossible. See Example 4. tan θ = 0.93

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1
Recall that the tangent function, \(\tan \theta\), is defined as the ratio of the sine and cosine functions: \(\tan \theta = \frac{\sin \theta}{\cos \theta}\).
Understand the range of the tangent function: \(\tan \theta\) can take any real value from \(-\infty\) to \(+\infty\), meaning it is not limited to values between -1 and 1 like sine and cosine.
Since \(\tan \theta = 0.93\) is a positive real number, check if this value lies within the possible range of tangent values. Because tangent can be any real number, 0.93 is within the possible range.
Conclude that there exists an angle \(\theta\) such that \(\tan \theta = 0.93\), so the statement is possible.
Optionally, to find such an angle \(\theta\), you would use the inverse tangent function: \(\theta = \tan^{-1}(0.93)\), which gives the principal value of the angle.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Definition of the Tangent Function

The tangent of an angle θ in a right triangle is the ratio of the length of the opposite side to the adjacent side. It can also be defined as tan θ = sin θ / cos θ, and its values can range from negative to positive infinity, depending on the angle.
추천 영상:
5:43
Introduction to Tangent Graph

Range and Possible Values of Tangent

The tangent function can take any real number value, meaning tan θ = 0.93 is possible. Since tangent is periodic with period π, multiple angles can have the same tangent value, and no restrictions prevent tan θ from being 0.93.
추천 영상:
5:08
Sine, Cosine, & Tangent of 30°, 45°, & 60°

Solving for Angles Given a Tangent Value

To find θ when tan θ = 0.93, use the inverse tangent function (arctan or tan⁻¹). This yields a principal value, and additional solutions can be found by adding integer multiples of π, reflecting the periodic nature of tangent.
추천 영상:
2:28
Solving Problems with Complementary & Supplementary Angles