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Ch. 6 - Inverse Circular Functions and Trigonometric Equations
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 41

Solve each equation for exact solutions.
arccos x + 2 arcsin √3/2 = π

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Recognize that the equation is \(\arccos x + 2 \arcsin \frac{\sqrt{3}}{2} = \pi\). Our goal is to solve for \(x\).
Evaluate the known inverse trigonometric value: find \(\arcsin \frac{\sqrt{3}}{2}\). Recall that \(\sin \frac{\pi}{3} = \frac{\sqrt{3}}{2}\), so \(\arcsin \frac{\sqrt{3}}{2} = \frac{\pi}{3}\).
Substitute this value back into the equation: \(\arccos x + 2 \times \frac{\pi}{3} = \pi\), which simplifies to \(\arccos x + \frac{2\pi}{3} = \pi\).
Isolate \(\arccos x\) by subtracting \(\frac{2\pi}{3}\) from both sides: \(\arccos x = \pi - \frac{2\pi}{3} = \frac{\pi}{3}\).
Use the definition of \(\arccos\) to solve for \(x\): since \(\arccos x = \frac{\pi}{3}\), then \(x = \cos \frac{\pi}{3}\). Recall that \(\cos \frac{\pi}{3} = \frac{1}{2}\).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Inverse Trigonometric Functions

Inverse trigonometric functions, such as arccos and arcsin, return the angle whose trigonometric ratio equals a given value. For example, arccos x gives the angle whose cosine is x, and arcsin y gives the angle whose sine is y. Understanding their ranges and outputs is essential for solving equations involving these functions.
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Solving trigonometric equations often involves isolating inverse functions, using identities, and applying domain restrictions. In this problem, combining inverse cosine and sine functions and using their properties allows finding exact solutions for x within the valid domain.
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