Solve each equation for exact solutions.
sin⁻¹ x - 4 tan⁻¹ (-1) = 2π

검증된 단계별 안내

Recognize that the equation is given as \(\sin^{-1} x - 4 \tan^{-1}(-1) = 2\pi\). Our goal is to solve for \(x\) in terms of exact values.

Evaluate the inverse tangent term \(\tan^{-1}(-1)\). Recall that \(\tan^{-1}(-1)\) is the angle whose tangent is \(-1\). Identify this angle within the principal range of \(\tan^{-1}\), which is \(\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)\).

Multiply the value of \(\tan^{-1}(-1)\) by 4, as indicated by the equation, to simplify the expression \(-4 \tan^{-1}(-1)\).

Rewrite the equation as \(\sin^{-1} x = 2\pi + 4 \tan^{-1}(-1)\), substituting the evaluated value from the previous step. This isolates \(\sin^{-1} x\) on one side.

Use the definition of \(\sin^{-1} x\) (the inverse sine function) to solve for \(x\). Recall that if \(\sin^{-1} x = \theta\), then \(x = \sin \theta\). Substitute the angle found in the previous step to express \(x\) exactly.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.

도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Inverse Trigonometric Functions

Inverse trigonometric functions, such as sin⁻¹(x) and tan⁻¹(x), return the angle whose sine or tangent is x. They are essential for solving equations where the variable is inside a trigonometric function, allowing us to isolate and find angle values.

Evaluating Inverse Tangent of Negative Values

The value of tan⁻¹(-1) corresponds to an angle whose tangent is -1, typically -π/4 in the principal range (-π/2, π/2). Understanding how to evaluate inverse tangent for negative inputs is crucial for simplifying and solving the given equation.

Solving Trigonometric Equations with Multiple Terms

When solving equations involving sums or differences of inverse trig functions, isolate the unknown term and use known values or identities to simplify. Recognizing how to manipulate and combine these terms helps find exact solutions within the correct domain.

Solve each equation for exact solutions.sin⁻¹ x - 4 tan⁻¹ (-1) = 2π