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Terms in this set (15)
What law is used to describe the refraction of a single ray of light at a flat boundary?
Snell's law is used to describe the refraction of a single ray of light at a flat boundary.
What happens when multiple rays of light from an object pass through a spherical boundary?
They refract and can form an image inside a different medium.
What determines whether the image formed by a spherical surface is real or virtual?
The shape of the surface and the sign of the focal length determine if the image is real or virtual.
What is the general image distance equation for refraction at a spherical surface?
The equation is n1/s_o + n2/s_i = (n2 - n1)/R, where n1 and n2 are refractive indices, s_o is object distance, s_i is image distance, and R is the radius of curvature.
How is the radius of curvature signed for a convex spherical surface?
For a convex surface, the radius of curvature is considered positive.
How is the radius of curvature signed for a concave spherical surface?
For a concave surface, the radius of curvature is considered negative.
What does a positive image distance indicate in the context of spherical surfaces?
A positive image distance indicates a real, inverted image.
What does a negative image distance indicate in the context of spherical surfaces?
A negative image distance indicates a virtual, upright image.
If an object is placed in air in front of a concave surface, what is the refractive index of the initial medium?
The refractive index of air is 1.
In the example given, what is the object distance if the object is 5 cm in front of the surface?
The object distance is +5 cm.
What is the refractive index behind the surface in the example problem?
The refractive index behind the surface is 1.44.
What is the radius of curvature for the concave surface in the example, and how is it signed?
The radius of curvature is -7 cm, negative because the surface is concave.
What is the calculated image distance in the example problem?
The image distance is -5.5 cm.
Is the image in the example real or virtual, and why?
The image is virtual because the image distance is negative.
What is the orientation of a virtual image formed by a spherical surface?