Precalculus
3cosα+sinα2\(\frac{\sqrt3\cos\alpha+\sin\alpha}{2}\)23cosα+sinα
3cosα−sinα2\(\frac{\sqrt3\cos\alpha-\sin\alpha}{2}\)23cosα−sinα
cosα+3sinα2\(\frac{\cos\alpha+\sqrt3\sin\alpha}{2}\)2cosα+3sinα
cosα−3sinα2\(\frac{\cos\alpha-\sqrt3\sin\alpha}{2}\)2cosα−3sinα