BackProperties of Square Roots and Solving Radical Equations
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Properties of Square Roots
Definition and Basic Properties
The square root of a number is a value that, when multiplied by itself, gives the original number. The principal (non-negative) square root of a number a is denoted as \( \sqrt{a} \).
Product Property: \( \sqrt{a} \cdot \sqrt{b} = \sqrt{ab} \) for all non-negative real numbers a and b.
Quotient Property: \( \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} \) for all non-negative real numbers a and positive b.
Square of a Square Root: \( (\sqrt{a})^2 = a \) for all non-negative real numbers a.
Example:
\( \sqrt{9} = 3 \) because \( 3^2 = 9 \).
\( \sqrt{16} \cdot \sqrt{25} = \sqrt{400} = 20 \).
\( \sqrt{\frac{49}{4}} = \frac{\sqrt{49}}{\sqrt{4}} = \frac{7}{2} \).

Simplifying Square Roots
Steps to Simplify Square Roots
To simplify a square root, factor the number under the radical into perfect squares and other factors, then apply the product property.
Step 1: Factor the radicand into perfect squares.
Step 2: Take the square root of the perfect square factors.
Step 3: Multiply the results.
Example:
\( \sqrt{72} = \sqrt{36 \times 2} = \sqrt{36} \cdot \sqrt{2} = 6\sqrt{2} \).
\( \sqrt{50} = \sqrt{25 \times 2} = 5\sqrt{2} \).
Solving Radical Equations
Definition and Steps
A radical equation is an equation in which the variable is inside a radical, usually a square root. To solve, isolate the radical and then square both sides to eliminate the radical.
Step 1: Isolate the radical on one side of the equation.
Step 2: Square both sides to eliminate the square root.
Step 3: Solve the resulting equation for the variable.
Step 4: Check all solutions in the original equation to avoid extraneous solutions.
Example:
Solve \( \sqrt{x+3} = 5 \):
Square both sides: \( x+3 = 25 \)
Solve for x: \( x = 22 \)
Check: \( \sqrt{22+3} = \sqrt{25} = 5 \) (valid solution)

Extraneous Solutions
Definition and Importance
When solving radical equations, squaring both sides can introduce extraneous solutions—solutions that do not satisfy the original equation. Always substitute your answers back into the original equation to verify their validity.
Example:
Solve \( \sqrt{x-1} = x-5 \):
Square both sides: \( x-1 = (x-5)^2 \)
Expand: \( x-1 = x^2 - 10x + 25 \)
Rearrange: \( 0 = x^2 - 11x + 26 \)
Factor: \( (x-13)(x-2) = 0 \) so \( x = 13 \) or \( x = 2 \)
Check:
For \( x = 13 \): \( \sqrt{13-1} = 12-5 = 8 \) and \( \sqrt{12} \approx 3.46 \neq 8 \) (not valid)
For \( x = 2 \): \( \sqrt{2-1} = 2-5 = -3 \) and \( \sqrt{1} = 1 \neq -3 \) (not valid)
No valid solutions.
Summary Table: Properties of Square Roots
Property | Algebraic Statement | Example |
|---|---|---|
Product Property | ||
Quotient Property | ||
Square of a Square Root |
Practice Problems
Simplify: \( \sqrt{18} \)
Solve: \( \sqrt{2x+1} = 7 \)
Simplify: \( \sqrt{32} \)
Solve: \( \sqrt{x+4} = x-2 \)

Additional Notes
Always check for extraneous solutions when solving radical equations.
Remember to simplify radicals as much as possible in your final answers.
