Beginning & Intermediate Algebra
Expand (x+m)(x+n)=x2+nx+mx+mn=x2+(m+n)x+mn(x + m)(x + n) = x^2 + nx + mx + mn = x^2 + (m + n)x + mn, so comparing coefficients gives m+n=bm + n = b and mn=cmn = c
Expand (x+m)(x+n)=x2+m2+n2+mn(x + m)(x + n) = x^2 + m^2 + n^2 + mn, and by equating coefficients we get m+n=bm + n = b and mn=cmn = c which follows from rearranging terms
Assume (x+m)(x+n)=x2+bx+c(x + m)(x + n) = x^2 + bx + c and substitute x=1x = 1 to obtain m+n=bm + n = b and x=0x = 0 to get mn=cmn = c so these must hold for all xx
Multiply termwise to get x2+m+n+mnx^2 + m + n + mn but since xx terms disappear we set m+n=bm + n = b and mn=cmn = c