Beginning & Intermediate Algebra
Contradiction. No solutions, because simplification leads to a false numeric statement 2=02 = 0.
Conditional. The solution set is {1}\(\left\[\lbrace\)1\(\right\]\rbrace\).
Conditional. The solution set is {0}\(\left\[\lbrace\)0\(\right\]\rbrace\).
Identity. All real numbers satisfy the equation.