A projectile is launched vertically upwards and its height above the ground after t t t seconds is given by the function h ( t ) = 50 t − 5 t 2 h(t) = 50t - 5t^2 h ( t ) = 50 t − 5 t 2 , where 0 ≤ t < 10 0\le t<10 0 ≤ t < 10 . At what time is the projectile at its maximum height?

6. Graphical Applications of Derivatives - Part 1 of 2

6. Graphical Applications of Derivatives / Intro to Extrema / Problem 3

Problem 3

A projectile is launched vertically upwards and its height above the ground after $t$ seconds is given by the function $h(t) = 50t - 5t^2$ , where $0\le t<10$ . At what time is the projectile at its maximum height?

$t equals 5$ $s$

$t equals 10$ $s$

$t equals 15$ $s$

$t equals 20$ $s$