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Question

Calculate the critical points for the function $p (x) = 2 x^{4} - 16 x^{2} + 32$ on the interval $open bracket negative 2 comma 3 close bracket$ . Identify the absolute maximum and minimum values.

Accepted Answer

Critical points: $x=\left\lbrace-2,0,2\right\rbrace$

$p_{\min}\left(-2\right)=0$ and $p_{\min}\left(2\right)=0$

$p_{\max}\left(3\right)=50$

Answer

Critical points: $x=\left\lbrace-2,0,2\right\rbrace$

$p_{\min}\left(-2\right)=0$ and $p_{\min}\left(2\right)=0$

$p sub max of 0 equals 50$

Answer

Critical points: $x=\left\lbrace-2,0,2\right\rbrace$

$p_{\min}\left(-2\right)=0$ $p_{\min}\left(2\right)=0$

$p sub max of 2 equals 50$

Answer

Critical points: $p (x) = 2 x^{4} - 16 x^{2} + 32$

$p_{\min}\left(-2\right)=0$ and $p_{\min}\left(2\right)=0$

$p_{\max}\left(3\right)=50$

Calculate the critical points for the function p(x)=2x4−16x2+32p(x) = 2x^4 - 16x^2 + 32 on the interval [−2,3][-2, 3]. Identify the absolute maximum and minimum values.

Calculate the critical points for the function $p (x) = 2 x^{4} - 16 x^{2} + 32$ on the interval $open bracket negative 2 comma 3 close bracket$ . Identify the absolute maximum and minimum values.