determine-the-coordinates-of-the-points-where-the-curve-x22xy4y28x2-2xy-4y2-8-in

Question

Determine the coordinates of the points where the curve $x^{2} - 2 x y + 4 y^{2} = 8$ intersects the $x$ -axis, and find the slopes of the curve at these points.

Accepted Answer

Points: $(2\sqrt{2}, 0)$ and $(-2\sqrt{2}, 0)$

Slope at both points: $1$

Answer

Points: $(2\sqrt{2}, 0)$ and $(-2\sqrt{2}, 0)$

Slope at both points: $-1$

Answer

Points: $x^{2} - 2 x y + 4 y^{2} = 8$ and $(-2\sqrt{2}, 0)$

Slope at $open paren the square root of 2 comma 0 close paren$ : $negative 1$

Slope at $(-2\sqrt{2}, 0)$ : $1$

Answer

Points: $(2\sqrt{2}, 0)$ and $(-2\sqrt{2}, 0)$

Slope at $(\sqrt{2},0)$ : $1$

Slope at $(-2\sqrt{2}, 0)$ : $negative 1$

Determine the coordinates of the points where the curve x2−2xy+4y2=8x^2 - 2xy + 4y^2 = 8 intersects the xx-axis, and find the slopes of the curve at these points.

Determine the coordinates of the points where the curve $x^{2} - 2 x y + 4 y^{2} = 8$ intersects the $x$ -axis, and find the slopes of the curve at these points.