Business Calculus
z′=cos(t+z)−1z^{\(\prime\)}=\(\cos\]\left\)(t+z\(\right\))-1
z′=sec(t+z)+1z^{\(\prime\)}=\(\sec\]\left\)(t+z\(\right\))+1
z′=sec(t+z)−1z^{\(\prime\)}=\(\sec\]\left\)(t+z\(\right\))-1
z′=cos(t+z)+1z^{\(\prime\)}=\(\cos\]\left\)(t+z\(\right\))+1