Calculus
f′(x)=3x2−15x+4(3x2+4)5f^{\prime}\left(x\right)=\frac{3x^2-15x+4}{\left(3x^2+4\right)^5}
f′(x)=4−27x2x(3x2+4)f^{\prime}\left(x\right)=\frac{4-27x^2}{x\left(3x^2+4\right)}
f′(x)=30x2−4x(3x2+4)f^{\prime}\left(x\right)=\frac{30x^2-4}{x\left(3x^2+4\right)}
f′(x)=27x2−4x2(3x2+4)f^{\prime}\left(x\right)=\frac{27x^2-4}{x^2\left(3x^2+4\right)}