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Calculus Final - Part 2 of 2
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Problem 1
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Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
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Problem 11
Problem 12
Problem 13
Problem 14
Calculus Final - Part 2 of 2
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8. Definite Integrals / Fundamental Theorem of Calculus / Problem 5
Problem 5
Find
d
d
x
∫
−
1
x
(
3
t
2
−
2
t
)
d
t
\frac{d}{dx} \int_{-1}^{x} (3t^2 - 2t) \, dt
.
A
3
x
2
−
2
x
3x^2-2x
B
3
x
2
3x^2
C
−
2
x
-2x
D
3
2
x
2
−
x
\frac32x^2-x
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