Calculus
Determine the velocity of the ball after tt seconds which is launched straight up from the top of a building with an initial speed of 40 ft/s40\text{ ft/s} from a height of 60 ft60\text{ ft} above the ground. The height (in feet) of the ball above the ground tt seconds after it is launched is given by the equation h(t)=−16t2+40t+60h(t)=-16t^2+40t+60.
The position of a cyclist moving in a straight line is described by the function p(t)=20t−5t2p(t)=20t-5t^2, where pp is in kilometers and tt is in hours. Find the intervals where the cyclist's speed is increasing for 0≤t≤50 ≤ t ≤ 5.
A diver jumps off a diving board 1010 feet above the pool with an initial upward velocity of 16 ft/s16\text{ ft/s}. The height (in feet) of the diver above the water tt seconds after the jump is given by s(t)=−16t2+16t+10s(t)=-16t^2+16t+10. What is the maximum height of the diver above the water?