a-diver-jumps-off-a-diving-board-10-feet-above-the-pool-with-an-initial-upward-v

Question

A diver jumps off a diving board $10$ feet above the pool with an initial upward velocity of $16 ft slash s$ . The height (in feet) of the diver above the water $t$ seconds after the jump is given by $s (t) = - 16 t^{2} + 16 t + 10$ . What is the maximum height of the diver above the water?

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A diver jumps off a diving board 1010 feet above the pool with an initial upward velocity of 16 ft/s16\text{ ft/s}. The height (in feet) of the diver above the water tt seconds after the jump is given by s(t)=−16t2+16t+10s(t)=-16t^2+16t+10. What is the maximum height of the diver above the water?

A diver jumps off a diving board $10$ feet above the pool with an initial upward velocity of $16 ft slash s$ . The height (in feet) of the diver above the water $t$ seconds after the jump is given by $s (t) = - 16 t^{2} + 16 t + 10$ . What is the maximum height of the diver above the water?