A 20.0-mL sample of 0.115 M sulfurous acid (H2SO3) solution is
ti...

Question

A 20.0-mL sample of 0.115 M sulfurous acid (H2SO3) solution is
titrated with 0.1014 M KOH. At what added volume of base solution
does each equivalence point occur?

Accepted Answer

Hi everyone here we have a question asking us in the tight rations of 15. mL of 0.11311 Moeller. Carbonic acid with 0.129 moller, sodium hydroxide, How much volume of the base is needed to reach each equivalence point. So carbonic acid is H two CO three, which is a die protic acid. So it will have to equivalence points. So we have 15 million l times one leader Over ml And our middle leaders are canceling out. And that gives us 0.015 L. So we have 0.015 l times zero . moles of carbonic acid divided by one liter. And our leaders are canceling out and that gives us 1.695 times 10 to the -3 moles. Now we have 1. Times 10 to the -3 moles. And we're going to multiply that by one leader Over 0. moles, sodium hydroxide, Which equals 0. L, which is the first equivalence point. And then we have to times zero point zero L Which equals 0.0262 L Which is our 2nd equivalence point. And those are our two answers, thank you for watching. Bye.

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