An isotonic solution contains 0.90% NaCl mass to volume. Calculat...

Question

An isotonic solution contains 0.90% NaCl mass to volume. Calculate
the percent mass to volume for isotonic solutions containing
each solute at 25 °C. Assume a van’t Hoff factor of 1.9 for
all ionic solutes.
a. KCl

Accepted Answer

Hello everyone today we are being asked to calculate the percent mass to volume for a solution that contains RB cl rubidium chloride at 25 degrees Celsius in a solution that contains 1.21% K C. L. Master volume. And we have to assume That there's a van Hoff factor of 1.7. So in doing this we have to note the molar masses of each compound that we have. So we see the molar mass of rubidium chloride Is going to be 119.91 g per mall Andy Mueller mass for KC. L. is going to be 74.55 g per mole. Next we must also assume just like we assume that there's a van Hoff factor 1.7 we must assume that we are acting in 100 g of a solution. Mhm. To soften our percent, we have to use to a geometry. So we take what we're given which is our 1.21%. And we convert that to grams by multiplying by 100. So you have 1.21 g of calcium potassium chloride. We multiplied by the molar mass ratio. So we say one mole of K C L is equal to 74.55 g of K C L. Next we have to do the multiple ratio between potassium chloride and rubidium chloride. And in doing that we can know that we have for every one mole of K C L. We have one mole of rubidium chloride. Next we have to do what we did with potassium chloride and multiply by the molar mass ratio. So we see that one roll of rubidium chloride on the bottom here is equal to that 119.91 g of rubidium chloride. Our units are going to cancel out, and we are going to be left with 1.95%. As our final answer. I hope this helped ahead until next time.

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