To determine the weight percent of carbon in sucrose, we start by recognizing that weight percent and mass percent are equivalent. The formula for calculating mass percent is:
Mass Percent of Carbon = \(\frac{\text{grams of carbon}}{\text{grams of sucrose}} \times 100\)
Sucrose has the chemical formula \(C_{12}H_{22}O_{11}\), which indicates it contains 12 carbon (C) atoms, 22 hydrogen (H) atoms, and 11 oxygen (O) atoms. To find the total mass of each element, we multiply the number of atoms by their respective atomic masses from the periodic table:
- Mass of Carbon: \(12 \times 12.01 \, \text{g/mol} = 144.12 \, \text{g}\)
- Mass of Hydrogen: \(22 \times 1.008 \, \text{g/mol} = 22.176 \, \text{g}\)
- Mass of Oxygen: \(11 \times 16.00 \, \text{g/mol} = 176.00 \, \text{g}\)
Next, we sum these masses to find the total mass of sucrose:
Total Mass of Sucrose = \(144.12 \, \text{g} + 22.176 \, \text{g} + 176.00 \, \text{g} = 342.296 \, \text{g}\)
Now, we can substitute the values into the mass percent formula:
Mass Percent of Carbon = \(\frac{144.12 \, \text{g}}{342.296 \, \text{g}} \times 100 \approx 42.1\%\)
Thus, the weight percent of carbon in sucrose is approximately 42.1%.
