At what atomic number is the filling of a g orbital likely to beg...

Question

At what atomic number is the filling of a g orbital likely to begin?

Accepted Answer

Hello everyone today. We are the following problem identify the atomic number where the eight s orbital starts to be filled. So to do this we must first apply the off ball principle which explains how our orbital's are filled and what order they're filled in. And so we're going to start with our one S orbital we're gonna fill all of that. So that's going to be one S. Two and then we're going to go to our two S. Two in our second period. We're still in our second period but we're not on the right hand side of the periodic table. And so we're not two p. 6. We move to the next row three s. 2 Right hand side, three p. 6. We're in the 4th period four s. 2 we go across but instead we're going to encounter the transition metals. And so our transition metals are always going to start with one less than our s orbital. So for four s we're going to go to our three D. And so we're filling in all of those elements. So that's going to be three D. 10. And then we're going to move to we're going to move further across to the right hand side. We're still in the fourth period the S. And the P. Are going to be equal in terms of their energy level. So they're going to have four P. Six Energy Level five or the fifth sub shell. So we're gonna have the fifth energy level. So we're gonna have five S. Two. We're gonna go down here to save one space as we cross from four s, we now go into five S and five s. Goes into our four D. 10, Which then feeds into our five p 6. Remember our S&R. P are on the same energy level? We are now in the sixth energy level. So we have six S. Two, and in the sixth energy level is when we encounter the F sub shell, and so are F sub shell is always going to start at four. So we look at our s orbital's and we just count to down for the energy level. So we're at six S two, so we go to four F. And those can accommodate 14 electrons. So we fill those in from F, we moved back up to the D. So that's going to be five D. 10. Remember we already encountered three D. And four D. So now we're at five D. After he moved into the D. We are back into the p orbital. Remember our S and R P orbital are going to be the same. So it's going to be six P six. We moved down to seven S. Two because we're in the seventh energy level, We encountered four F 14. So next must be five F 14, moved out here, we are now In the six energy levels. So we have our now that we are in our next energy level, we go from five F 14 and this is where it gets tricky, we move onto six, but this time it's going to be D 10, so we're not going to, so we're gonna go from seven S two F two D. So S. F two D. And then from our six D 10, we're going to move to our seven P six. Remember S and P. S are always in the same energy level, We're now in the 8th energy level. And lastly, this is where we're gonna stop. So we're going to have eight s. One because one is when we start to fill in our orbital and what we're gonna do, we're gonna count up all of these numbers that are exponents. So every single number that I am boxing around is going to get added up. And when we add up all of these numbers, they are going to give us a value. And that value is going to be 119 As we have 119 electrons. And so with that we've answered the question overall, I hope that this helped. And until next time

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