Write a balanced chemical equation for the reaction of boron trifluoride (BF₃) gas with water to form boric acid (H₃BO₃) and hydrogen fluoride (HF).

• A. BF₃(g) + 3 H₂O(l) → H₃BO₃(aq) + 3 HF(g)
• B. 2 BF₃(g) + 6 H₂O(l) → 2 H₃BO₃(aq) + 6 HF(g)
• C. BF₃(g) + 2 H₂O(l) → 2 H₃BO₃(aq) + 6 HF(aq)
• D. 3 BF₃(g) + 9 H₂O(l) → 3 H₃BO₃(aq) + 9 HF(aq)

Answer: (A)