Give the balanced nuclear reaction for the decay of indium-113, which results in silver-109 formation.

• A. ¹¹³₄₉In → ¹⁰⁹₄₇Ag + ⁰₀γ
• B. ¹¹³₄₉In → ¹⁰⁹₄₇Ag + ⁴₂He
• C. ¹¹³₄₉In → ¹⁰⁹₄₇Ag
• D. ¹¹³₄₉In → ¹⁰⁹₄₇Ag + ⁰₋₁e

Answer: (B)