The Pb²⁺ ion can be precipitated using the Cl^– ion. Calculate the volume (in mL) of 0.11 M HCl solution required to react with 40.0 mL of 0.26 M Pb(NO₃)₂. Determine the mass (in grams) of PbCl₂ formed.

• A. 84.6 mL HCl
  1.32 g PbCl₂
• B. 114 mL HCl
  1.62 g PbCl₂
• C. 242 mL HCl
  3.76 g PbCl₂
• D. 189 mL HCl
  2.89 g PbCl₂

Answer: (D)