Question 1

A weather balloon is released at ground level where the pressure is 1.00 atm and the temperature is 300 K. As it rises to a higher altitude, the pressure drops to 0.60 atm and the temperature decreases to 270 K. If the initial volume of the balloon is 2.0 L, what will be its new volume? Use the combined gas law: $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.

Accepted Answer

$V_2 = 3.7\ 	ext{L}$

Question 2

Which of the following best describes what happens to the pressure and volume of a weather balloon as it rises through the atmosphere, assuming temperature decreases slightly?

Accepted Answer

Pressure decreases and volume increases.

Question 3

If a weather balloon at sea level has a volume of 5.0 L at a pressure of 1.00 atm and a temperature of 298 K, what will its volume be at a pressure of 0.50 atm and a temperature of 273 K? Use $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.

Accepted Answer

$V_2 = 10.9\ 	ext{L}$

Question 4

A weather balloon contains 3.0 L of gas at 1.2 atm and 290 K. If the balloon rises and the pressure drops to 0.8 atm while the temperature remains constant, what is the new volume? Use Boyle's Law: $P_1 V_1 = P_2 V_2$.

Accepted Answer

$V_2 = 4.5\ 	ext{L}$

Question 5

Which equation would you use to calculate the change in volume of a weather balloon as it rises, if both pressure and temperature change?

Accepted Answer

$\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$

Question 6

A weather balloon is filled with 4.0 L of gas at 1.0 atm and 300 K. If the balloon rises to a region where the pressure is 0.75 atm and the temperature is 250 K, what is the new volume? Use $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.

Accepted Answer

$V_2 = 4.0\ 	ext{L}$

Question 7

If the temperature of a weather balloon remains constant as it rises and the pressure decreases, what happens to the volume of the balloon according to Boyle's Law?

Accepted Answer

The volume increases.

Question 8

A weather balloon at 1.00 atm and 273 K has a volume of 2.5 L. If the pressure drops to 0.50 atm and the temperature increases to 300 K, what is the new volume? Use $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.

Accepted Answer

$V_2 = 5.5\ 	ext{L}$

Question 9

Which of the following statements is true about the behavior of a weather balloon as it rises through the atmosphere?

Accepted Answer

The balloon expands because the external pressure decreases.

Question 10

A weather balloon is released at 1.00 atm and 298 K with a volume of 1.5 L. At a higher altitude, the pressure is 0.80 atm and the temperature is 273 K. What is the new volume? Use $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.

Accepted Answer

$V_2 = 1.64\ 	ext{L}$

Gas Laws: Pressure and Volume Changes in a Rising Weather Balloon

Study Guide - Practice Questions

Study Guide - Flashcards