compute-the-definite-integral-using-trigonometric-substitution832864x2-dxint8sqr

Question

Compute the definite integral using trigonometric substitution:∫83/2864−x2 dx\int_{8\sqrt{3}/2}^8\sqrt{64 - $$x^2$$}\,dx

Accepted Answer

16π−2433\frac{16\pi-24\sqrt3}{3}

Answer

16π+2433\frac{16\pi+24\sqrt3}{3}

Answer

16π3\frac{16\pi}{3}

Answer

π3\frac{\pi}{3}

Compute the definite integral using trigonometric substitution:∫83/2864−x2dx\(\int\)_{8\(\sqrt{3}\)/2}^8\(\sqrt{64 - x^2}\)\,dx