evaluate-the-integral-03tan22tan5sec2-d-int0frac3-tan2-2-tan-5-sec2-d

Question

Evaluate the integral: ∫0π3(tan⁡2θ−2tan⁡θ+5)sec⁡2θ  dθ\$$int_0$$^{\frac{π}{3}}(\$$tan^2$$	heta-2	an	heta+5)\$$sec^2$$	heta\,	ext{ }d	heta

Accepted Answer

63−36\sqrt3-3

Answer

−43−3-4\sqrt3-3

Answer

43−34\sqrt3-3

Answer

−63−3-6\sqrt3-3

Evaluate the integral: ∫0π3(tan2θ−2tanθ+5)sec2θ dθ\(\int\)_0^{\(\frac{π}{3}\)}(\(\tan\)^2\(\theta\)-2\(\tan\)\(\theta\)+5)\(\sec\)^2\(\theta\)\,\(\text{ }\)d\(\theta\)