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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 5, Problema 5.4.45c

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.
(c) The average value of a linear function on an interval [a, b] is the function value at the midpoint of [a, b] .

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Step 1: Recall the formula for the average value of a function f(x) on an interval [a, b]. It is given by: 1(b-a)∫abf(x)dx.
Step 2: For a linear function, f(x) = mx + c, substitute this into the formula for the average value. The integral becomes: ∫ab(mx+c)dx.
Step 3: Compute the integral of the linear function. The integral of mx is m2x2, and the integral of c is cx. Evaluate these terms at the bounds a and b.
Step 4: Simplify the result of the integral and divide by (b - a) to find the average value. After simplification, the average value of the linear function will be: m((a+b)2)+c, which is the function value at the midpoint of [a, b].
Step 5: Conclude that the statement is true. The average value of a linear function on an interval [a, b] is indeed equal to the function value at the midpoint of [a, b], as shown by the calculation.

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Average Value of a Function

The average value of a function f(x) over an interval [a, b] is calculated using the formula (1/(b-a)) * ∫[a to b] f(x) dx. This concept is crucial for understanding how to find the mean value of a function across a specified range, which can differ from simply evaluating the function at a single point.
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Average Value of a Function

Linear Functions

A linear function is a polynomial function of degree one, typically expressed in the form f(x) = mx + b, where m is the slope and b is the y-intercept. The properties of linear functions, such as constant slope and direct proportionality, influence how their average value behaves over an interval.
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Midpoint of an Interval

The midpoint of an interval [a, b] is calculated as (a + b)/2. For linear functions, evaluating the function at this midpoint can yield the average value, but this is not true for non-linear functions. Understanding this concept helps clarify why the statement may hold true specifically for linear functions.
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Left, Right, & Midpoint Riemann Sums
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