evaluate-the-integralt24t323-dt-int-t2-4t3-23-dt

Question

Evaluate the integral.∫t2(4t3−2)3 dt \int $$t^2$$ $$(4t^3$$ - $$2)^3$$\, dt

Accepted Answer

(2t3−1)43+C\frac{\$$left(2t^3-1$$\$$right)^4$$}{3}+C

Answer

(2t3+1)43+C\frac{\$$left(2t^3+1$$\$$right)^4$$}{3}+C

Answer

(t3−2)34+C\frac{\$$left(t^3-2$$\$$right)^3$$}{4}+C

Answer

(t3+2)34+C\frac{\$$left(t^3+2$$\$$right)^3$$}{4}+C

Evaluate the integral.∫t2(4t3−2)3dt \(\int\) t^2 (4t^3 - 2)^3\, dt