Calculus
5tan(5x−1)+C{\(\displaystyle\)5\(\tan\)\(\left\)(5x-1\(\right\))+C}
15tan(5x−1)+C\(\displaystyle\[\frac\)15\(\tan\]\left\)(5x-1\(\right\))+C
15tanx+C{\(\displaystyle\)\(\frac\)15\(\tan\) x+C}
15sec(5x−1)+C{\(\displaystyle\[\frac\)15\(\sec\]\left\)(5x-1\(\right\))+C}