Ch. 1 - Functions

Briggs - Calculus: Early Transcendentals 3rd Edition

Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo

Briggs 3rd Edition

Ch. 1 - Functions

Problema 1.20

Capitolo 1, Problema 1.20

For a certain constant a>1, ln a≈3.8067 . Find approximate values of log₂ a and logₐ 2 using the fact that ln 2≈0.6931.

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Use the change of base formula for logarithms: \( \log_b a = \frac{\ln a}{\ln b} \).

To find \( \log_2 a \), apply the formula: \( \log_2 a = \frac{\ln a}{\ln 2} \).

Substitute the given values: \( \ln a \approx 3.8067 \) and \( \ln 2 \approx 0.6931 \).

Calculate \( \log_2 a \) using the substituted values: \( \log_2 a = \frac{3.8067}{0.6931} \).

To find \( \log_a 2 \), use the reciprocal property of logarithms: \( \log_a 2 = \frac{1}{\log_2 a} \).

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Change of Base Formula

The change of base formula allows us to convert logarithms from one base to another. It states that log_b(x) = log_k(x) / log_k(b) for any positive k. This is particularly useful when we need to compute logarithms in a base that is not readily available, such as converting natural logarithms (ln) to base 2 or base a.

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Change of Base Property

Natural Logarithm (ln)

The natural logarithm, denoted as ln, is the logarithm to the base e, where e is approximately 2.71828. It is a fundamental concept in calculus and is used extensively in various applications, including growth models and compound interest. In this problem, ln a and ln 2 are provided, which are essential for calculating log₂ a and logₐ 2.

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Derivative of the Natural Logarithmic Function

Approximation of Logarithmic Values

In this context, approximating logarithmic values involves using known logarithmic values to estimate others. Given ln a and ln 2, we can derive log₂ a and logₐ 2 using the change of base formula. This method is particularly useful when exact values are difficult to compute, allowing for practical estimations in mathematical problems.

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