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Ch. 11 - Power Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 11, Problema 11.4.22

Limits Evaluate the following limits using Taylor series.
lim ₓ→∞ x(e¹/ˣ − 1)

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Recognize that the limit involves the expression \(x \left(e^{1/x} - 1\right)\) as \(x\) approaches infinity, which suggests using the Taylor series expansion of the exponential function around 0.
Recall the Taylor series expansion for \(e^t\) around \(t=0\): \[e^t = 1 + t + \frac{t^2}{2!} + \frac{t^3}{3!} + \cdots\]
Substitute \(t = \frac{1}{x}\) into the series to get: \[e^{1/x} = 1 + \frac{1}{x} + \frac{1}{2x^2} + \frac{1}{6x^3} + \cdots\]
Rewrite the original expression using this expansion: \[x \left(e^{1/x} - 1\right) = x \left(\frac{1}{x} + \frac{1}{2x^2} + \frac{1}{6x^3} + \cdots \right)\]
Simplify the expression by multiplying \(x\) inside the parentheses and then analyze the behavior of each term as \(x \to \infty\) to determine the limit.

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Limits at Infinity

Limits at infinity describe the behavior of a function as the input grows without bound. Understanding how functions behave as x approaches infinity helps determine if the function approaches a finite value, infinity, or does not exist.
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Cases Where Limits Do Not Exist

Taylor Series Expansion

A Taylor series represents a function as an infinite sum of terms calculated from its derivatives at a single point. It approximates functions near that point, allowing simplification of complex expressions, especially useful for evaluating limits.
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Taylor Series

Exponential Function and Its Expansion

The exponential function e^x can be expanded as a Taylor series: e^x = 1 + x + x²/2! + ... . For small values of x, this expansion helps approximate e^(1/x) and analyze the limit by substituting the series into the expression.
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Exponential Functions
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{Use of Tech} Newton's derivation of the sine and arcsine series Newton discovered the binomial series and then used it ingeniously to obtain many more results. Here is a case in point.

a. Referring to the figure, show that x = sin s or s = sin ⁻¹ x.

b. The area of a circular sector of radius r subtended by an angle θ is 1/2r²θ. Show that the area of the circular sector APE is s/2, which implies that

s = 2 ∫₀ˣ √(1 − t²) dt − x √(1 −x²)

c. Use the binomial series for f(x) = √(1 − x²) to obtain the first few terms of the Taylor series for s=sin ⁻¹ x.

d. Newton next inverted the series in part (c) to obtain the Taylor series for x=sin s. He did this by assuming sin s = ∑ aₖ sᵏ and solving x = sin(sin ⁻¹ x) for the coefficients aₖ. Find the first few terms of the Taylor series for sin s using this idea (a computer algebra system might be helpful as well).

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Manipulating Taylor series Use the Taylor series in Table 11.5 to find the first four nonzero terms of the Taylor series for the following functions centered at 0.


(1 + x⁴)⁻¹

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Power series for derivatives


a. Differentiate the Taylor series centered at 0 for the following functions.

b. Identify the function represented by the differentiated series.

c. Give the interval of convergence of the power series for the derivative.


f(x) = (1 − x)⁻¹

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Suppose f(0)=1, f'(0)=0, f''(0)=2, and f⁽³⁾(0)=6. Find the third-order Taylor polynomial for f centered at 0 and use it to approximate f(0.2).

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Approximating real numbers Use an appropriate Taylor series to find the first four nonzero terms of an infinite series that is equal to the following numbers.

√e

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Limits Evaluate the following limits using Taylor series.

lim ₓ→₄ (x² 16)/(ln (x 3)}

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