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Ch. 11 - Power Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 11, Problema 11.3.41

Manipulating Taylor series Use the Taylor series in Table 11.5 to find the first four nonzero terms of the Taylor series for the following functions centered at 0.


(1 + x⁴)⁻¹

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Recall the Taylor series for the function \( \frac{1}{1 - x} = \sum_{n=0}^{\infty} x^n = 1 + x + x^2 + x^3 + \cdots \), which is valid for \( |x| < 1 \).
Notice that the given function \( (1 + x^4)^{-1} \) can be rewritten as \( \frac{1}{1 - (-x^4)} \). This means we can use the geometric series formula by substituting \( -x^4 \) in place of \( x \).
Substitute \( -x^4 \) into the geometric series to get the Taylor series: \[ \frac{1}{1 + x^4} = \sum_{n=0}^{\infty} (-x^4)^n = \sum_{n=0}^{\infty} (-1)^n x^{4n} = 1 - x^4 + x^8 - x^{12} + \cdots \]
Identify the first four nonzero terms from the series expansion: these are the terms corresponding to \( n = 0, 1, 2, 3 \), which are \( 1, -x^4, x^8, -x^{12} \).
Write the final Taylor series approximation centered at 0 using these four terms: \[ 1 - x^4 + x^8 - x^{12} \]. This is the first four nonzero terms of the Taylor series for \( (1 + x^4)^{-1} \).

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