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Ch. 11 - Power Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 11, Problema 11.4.76a

Probability: sudden−death playoff Teams A and B go into suddendeath overtime after playing to a tie. The teams alternate possession of the ball, and the first team to score wins. Assume each team has a 1/6 chance of scoring when it has the ball, and Team A has the ball first.


a. The probability that Team A ultimately wins is ∑ₖ₌₀∞ (1/6)(5/6)²ᵏ. Evaluate this series.

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1
Recognize that the given series is an infinite geometric series of the form \(\sum_{k=0}^\infty ar^k\), where the first term \(a = \frac{1}{6}\) and the common ratio \(r = \left(\frac{5}{6}\right)^2\).
Recall the formula for the sum of an infinite geometric series when \(|r| < 1\): \(S = \frac{a}{1 - r}\).
Substitute the values of \(a\) and \(r\) into the formula: \(S = \frac{\frac{1}{6}}{1 - \left(\frac{5}{6}\right)^2}\).
Simplify the denominator by calculating \(\left(\frac{5}{6}\right)^2 = \frac{25}{36}\), so the denominator becomes \(1 - \frac{25}{36}\).
Express the denominator as a single fraction and then write the sum \(S\) as a simplified fraction or decimal (without calculating the final numeric value).

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Geometric Series

A geometric series is a sum of terms where each term is a constant multiple (common ratio) of the previous one. It has the form ∑ ar^k, and if |r| < 1, the series converges to a/(1-r). This concept is essential for evaluating infinite sums like the one given in the problem.
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In problems involving repeated trials until success, probabilities often form infinite sums representing all possible outcomes. Understanding how to express and evaluate these sums helps determine the total probability of an event occurring eventually, such as Team A winning in sudden-death overtime.
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