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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.4.26

Derivatives Find and simplify the derivative of the following functions.
f(x) = 2e^x-1 / 2e^x+1

Guida verificata passo dopo passo
1
Step 1: Identify the function f(x) = \(\frac{2e^x - 1}{2e^x + 1}\). This is a rational function, which means we will use the quotient rule to find its derivative.
Step 2: Recall the quotient rule for derivatives: if you have a function \( g(x) = \frac{u(x)}{v(x)} \), then the derivative \( g'(x) \) is given by \( \frac{u'(x)v(x) - u(x)v'(x)}{(v(x))^2} \).
Step 3: Assign \( u(x) = 2e^x - 1 \) and \( v(x) = 2e^x + 1 \). Compute the derivatives: \( u'(x) = 2e^x \) and \( v'(x) = 2e^x \).
Step 4: Substitute \( u(x) \), \( v(x) \), \( u'(x) \), and \( v'(x) \) into the quotient rule formula: \( f'(x) = \frac{(2e^x)(2e^x + 1) - (2e^x - 1)(2e^x)}{(2e^x + 1)^2} \).
Step 5: Simplify the expression obtained in Step 4 by expanding the terms in the numerator and combining like terms.

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