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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.4.99b

Product Rule for three functions Assume f, g, and h are differentiable at x.
b. Use the formula in (a) to find d/dx(e^x(x−1)(x+3))

Guida verificata passo dopo passo
1
Step 1: Identify the functions involved in the product. Here, we have three functions: \(f(x) = e^x\), \(g(x) = (x - 1)\), and \(h(x) = (x + 3)\). We need to differentiate the product \(f(x)g(x)h(x)\).
Step 2: Recall the product rule for three functions. If \(u(x)\), \(v(x)\), and \(w(x)\) are differentiable functions, then the derivative of their product is given by: \(\frac{d}{dx}[u(x)v(x)w(x)] = u'(x)v(x)w(x) + u(x)v'(x)w(x) + u(x)v(x)w'(x)\).
Step 3: Differentiate each function individually. Compute \(f'(x)\), \(g'(x)\), and \(h'(x)\). For \(f(x) = e^x\), \(f'(x) = e^x\). For \(g(x) = (x - 1)\), \(g'(x) = 1\). For \(h(x) = (x + 3)\), \(h'(x) = 1\).
Step 4: Apply the product rule for three functions. Substitute \(f(x)\), \(g(x)\), \(h(x)\), and their derivatives into the formula: \(\frac{d}{dx}[e^x(x-1)(x+3)] = e^x \cdot (x-1)(x+3) + e^x \cdot 1 \cdot (x+3) + e^x \cdot (x-1) \cdot 1\).
Step 5: Simplify the expression. Combine like terms and simplify the expression obtained in Step 4 to get the final derivative.

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Product Rule

The Product Rule is a fundamental differentiation rule used to find the derivative of the product of two or more functions. For two functions f(x) and g(x), the rule states that the derivative of their product is given by f'(x)g(x) + f(x)g'(x). This concept extends to three functions, where the derivative of f(x)g(x)h(x) is f'(x)g(x)h(x) + f(x)g'(x)h(x) + f(x)g(x)h'(x).
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The Product Rule

Chain Rule

The Chain Rule is another essential differentiation technique that allows us to differentiate composite functions. If a function y is defined as a composition of two functions, such as y = f(g(x)), the Chain Rule states that the derivative is dy/dx = f'(g(x)) * g'(x). While not directly applied in the product rule, understanding the Chain Rule is crucial when dealing with functions that involve exponentials or other nested functions.
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Intro to the Chain Rule

Exponential Functions

Exponential functions, such as e^x, are functions where the variable appears in the exponent. The derivative of e^x is unique because it is equal to e^x itself, making it particularly straightforward to differentiate. In the context of the given problem, recognizing that e^x is part of the product allows for easier application of the Product Rule, as its derivative does not change the form of the function.
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Exponential Functions
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