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Ch. 4 - Applications of the Derivative
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.R.69

60–81. Limits Evaluate the following limits. Use l’Hôpital’s Rule when needed. 


lim_x→1 (x⁴ - x³ - 3x² + 5x -2) / x³ + x² - 5x + 3

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First, substitute x = 1 into the function to check if the limit results in an indeterminate form. Calculate the numerator: 1^4 - 1^3 - 3(1)^2 + 5(1) - 2 and the denominator: 1^3 + 1^2 - 5(1) + 3.
After substitution, if both the numerator and denominator evaluate to 0, the limit is in the indeterminate form 0/0, which means l'Hôpital's Rule can be applied.
Apply l'Hôpital's Rule by differentiating the numerator and the denominator separately. The derivative of the numerator (x^4 - x^3 - 3x^2 + 5x - 2) is 4x^3 - 3x^2 - 6x + 5.
The derivative of the denominator (x^3 + x^2 - 5x + 3) is 3x^2 + 2x - 5.
Evaluate the limit of the new function formed by the derivatives as x approaches 1: lim_x→1 (4x^3 - 3x^2 - 6x + 5) / (3x^2 + 2x - 5). Substitute x = 1 into this expression to find the limit.

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